Question

我有一个表'Notes'和列名'Note'，其值为Hi和Hello 看起来像这样

#include "stdafx.h"
#include <iostream>
#include <string>
#include <string.h>
#include <cstring>

using namespace std;

int main();
{
    //Get seed colour
    string seedColour = ""; //The empty "" is what "seedColor" will be chaned to after cin.
    cout << "Enter Seed Colour (Red/Blue?) \n";
    cin >> seedColour; //The user will iunput the seed's colour, which will change the empty "" and we now have (eg) "string seedColour = "red""

    //Get Temp
    int temp = 0;
        cout << "Enter the Temp \n";
    cin >> temp;

    //Get Soil Moisture
    string soilMoisture = "";
    cout >> "Is the soil Wet or dry? \n";
    cin >> soilMoisture;

        //if red seed
    if (seedColour == "red")
    {
        //if temp >= 75
        if (temp >= 75)
        {

            //if soil is wet
            if (soilMoisture == "wet")
            {
                //Output Sunflower
                cout << "SUNFLOWER LAR.\n";
            }
            //if soil dry
            if (soilMoisture == "dry")
            {
                //Dandelion
                cout << "Dandelion.\n";
            }

            //Otherwwise (temp <75)
            else
            {
                //Mushroom
                cout << "Mushroom";

            }
        }
    }

    //if blue
    if (seedColour == "blue")
    {
        //temp between 60 n 70
        if (temp >= 60 && temp <= 70)
        {
            //wet soil
            if (soilMoisture == "wet")
            {
                //Dandilion
                cout << "Dandilion \n";
            }

            //dry soil
            if (soilMoisture == "dry")
            {
                //Sunflower
                cout << "Sunflower";

            }
        }


        //Otherwise
        else
        {
            //mushroom
            cout << "Mushroom";
        }
    }
    return 0
}

我想在sql的两列中分隔它输出将是这样的：

Note
--------
HI
HELLO

我如何在sql查询中执行此操作？

Answer 1

此？如果有超过2行，它应该可以工作。

WITH    NotesWithId
AS      (
        SELECT ID = ROW_NUMBER() OVER (ORDER BY (SELECT NULL)),
               note
        FROM   Notes
        ) 
SELECT  [note1] = CASE WHEN [ID] % 2 <> 0 THEN [note] ELSE NULL END,
        [note2] = CASE WHEN [ID] % 2 = 0 THEN [note] ELSE NULL END
FROM    NotesWithId;

Answer 2

DECLARE
@SQL VARCHAR(1000),
@COLUMN_LIST VARCHAR(200)
SET @COLUMN_LIST=(SELECT  STUFF((SELECT ',[' + CONVERT(VARCHAR(5),NOTE ) +'] '
                        FROM (SELECT DISTINCT NOTE FROM #C)Z
                         FOR XML PATH('')),1,1,''))
SET @SQL=
'SELECT HI AS NOTE1 ,HELLO NOTE2  FROM 
(
SELECT NOTE AS NOTE FROM #C
)B
PIVOT
(
MIN(B.NOTE)   FOR B.NOTE IN ('+@COLUMN_LIST+')
)A'
SELECT @SQL
EXEC (@SQL)

Answer 3

怎么样：

select max(note) as note1, min(note) as note2
from t;

在一列中分隔两行并将其显示在两列中

3 个答案: