Question

我在openCV中使用projectPoints（）方法从3D获取2D数组。

我现在有一个2D数组，但我不知道如何处理这些点...

这可能听起来像一个愚蠢的问题，但我对openCV和一般的图形工作都很陌生。

我已将这些点保存为.txt文件，它看起来像这样：

[[[ 200.09907914  -82.06738337]]

 [[ 493.43350608  -75.61411136]]

 [[ 341.84147575  -76.85033738]]

 [[ 476.1858408   -44.00185036]]

 [[ 388.80711654  -23.52747913]]

 [[ 419.89479852  -80.92570616]]

 [[ 270.18706415  -78.77744771]]

 [[ 453.17295132  -38.22746564]]

 [[ 336.55951175  -78.23490512]]

 [[ 461.80562252  -50.39816719]]

 [[ 400.55422812  -69.06144546]]

 [[ 377.27021722  -30.25844784]]

 [[ 269.73447838  -81.67956696]]

 [[ 204.3975581   -64.63087857]]

 [[ 322.0647573   -50.91627825]]

 [[ 264.52576218  -62.21001649]]

 [[ 343.94977452  -18.27828932]]

 [[ 424.40214827  -19.53042058]]

 [[ 529.80110569  -30.70642375]]

 [[ 426.91725443  -19.8445123 ]]

 [[ 382.43526019  -16.33614303]]

 [[ 575.52868617  -29.50400229]]
    etc...

    [[ 180.53274111  319.29471839]]]
[[ -41.8973341   457.25621412  238.56738337 ...,   83.7946682   169.35134067
    -2.55510041]
 [-571.8835458    41.8973341   -77.90092086 ...,  398.60600403   83.7946682
    -7.82485769]
 [ 112.73208124  548.20593581  232.11411136 ..., -225.46416248
   435.35288301   28.52750401]
 ..., 
 [-499.21204508  -49.92094479 -140.9565395  ...,  211.70278173
   -99.84188958    1.82323202]
 [  35.77105875  464.99179761 -162.79471839 ...,  -71.5421175   123.99637881
    -0.59708278]
 [-503.32183347  -35.77105875  -97.46725889 ...,  200.65645054  -71.5421175
     0.9972777 ]]

你如何使用projectPoints（）的输出？

0 个答案: