Question

我是一个过于深入PHP的javascript人（即使这个问题不深）。

我在url中从文件传递两个不同的变量。一个人过得很好而另一个没有。

我有2个文件。 upload.php和uploadfiles.php。

params帮助构建文件上传的目的地。

这两个参数是“memberId”和“fileType”。

这是我将params传递给uploadfiles.php的地方，此代码在upload.php上。

它在两个地方。一个用于表单的隐藏输入，另一个作为var传递给flash脚本。

表格：

<input name="uploadscript" id="uploadscript" type="hidden" value="/flashuploader/FileProcessingScripts/PHP/uploadfiles.php?memberId=<?php echo $_REQUEST["memberId"] ?>&fileType=<?php echo $_REQUEST["fileType"] ?>" />

在js：

uploadUrl: '/flashuploader/FileProcessingScripts/PHP/uploadfiles.php?memberId=<?php echo $_REQUEST["memberId"] ?>&fileType=<?php echo $_REQUEST["fileType"] ?>'

我在upload.php上测试过$ _REQUEST [“fileType”]确实有正确的值。

然后我在uploadfiles.php上检索params，如下所示：

$uploaddir=realpath(dirname(__FILE__) . '/../../../memberimages/') . '/'.$_REQUEST["memberId"].'/My_Files/'.$_REQUEST["fileType"].'/';

Param“memberId”工作正常，但“fileType”为空。我确定这与我在upload.php上用php添加params到url的方式有关，但我没有想法。

这是由upload.php生成并返回的html。您可以在第44和80行看到值看起来正确：

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

<script type="text/javascript">

   function mysubmit(type)
   {
      if(document.getElementById("uploadscript").value=='')
      {
         window.alert('Enter upload processing script file name!');
         return false;
      }
      if(type=='flash')
      {        
         MultiPowUpload.uploadAll(document.getElementById("uploadscript").value); 
         document.getElementById("server_reply").value="";
      }
      else
      {
         var FormObj = document.getElementById("myform");
         FormObj.action = document.getElementById("uploadscript").value;
         return true;
      }
   }

   function MultiPowUpload_onComplete(type, index, serverResponse)
   {  
      var reply;
      reply = document.getElementById("server_reply");
      reply.value += "\nReply for file: " + MultiPowUpload.fileList()[index].name + "\r\n" + serverResponse + "\n";
   }
   var fileType = 'Video';
   function MultiPowUpload_onCompleteAbsolute(type, uploadedBytes)
   {
      if (fileType == 'Video'){
           parent.loadUserVideos();
      } else if (fileType == 'Images') {
           parent.loadUserImages();
      }
   }

  </script>

<div style="margin-top: -20px">
<input name="uploadscript" id="uploadscript" type="hidden" value="/flashuploader/FileProcessingScripts/PHP/uploadfiles.php?memberId=43&fileType=Video" />
<table width="380" cellpadding="0" cellspacing="0">
   <tr>
      <td style="position: relative;">
      <div id="MultiPowUpload_holder" style="margin-top: 20px">
      <table width="380" cellpadding="0" cellspacing="0">
         <tr>
            <td>
            <form id="myform" onSubmit="return mysubmit();"
               enctype="multipart/form-data" action="" method="POST">
            <table width="100%" border="0" cellspacing="0" cellpadding="0">
               <tr>
                  <td width="106"><span
                     style="font-family: Arial, Helvetica, sans-serif; font-size: 12px">Select
                  file:</span></td>
                  <td width="294"><input name="Filedata" type="file" /></td>
               </tr>
            </table>
            <br>
            <input type="submit" value="Upload File" /></form>
            </td>
         </tr>
      </table>
      </div>
      <!-- <img src="/images/ajax-loader.gif" style="position:absolute; top:40%; left:50%; margin-left:-110px;" /> -->
      <!-- SWFObject home page: http://code.google.com/p/swfobject/ --> <script
         type="text/javascript" src="/flashuploader/swfobject.js"></script> <script
         type="text/javascript">
         var params = {
            BGColor: "#FFFFFF"
         };
         var attributes = {
            id: "MultiPowUpload",
            name: "MultiPowUpload"
         };
         var flashvars = {
           uploadUrl: '/flashuploader/FileProcessingScripts/PHP/uploadfiles.php?memberId=43&fileType=Video',
           uploadButtonVisible: "Yes",
           useExternalInterface: "Yes",
           maxFileSize: "6024000",
           maxFileCount: "20",
           maxFileSizeTotal: "20480000",
           backgroundColor: "#FFFFFF",
           buttonTextColor: "#000000",
           buttonBackgroundColor: "#F1F1F1",
           buttonBottomBorderColor: "#E1E1E1",
           buttonTopBorderColor: "#E1E1E1",
           buttonDisabledBackgroundColor: "#FFFFFF",
           buttonDisabledBottomBorderColor: "#DDDDDD",
           buttonDisabledTopBorderColor: "#DDDDDD",
           buttonDisabledTextColor: "#DDDDDD", 
           buttonRollOverBottomBorderColor: "#666666",
           buttonRollOverTopBorderColor: "#666666",
           buttonDownBottomBorderColor: "#000000",
           buttonDownTopBorderColor: "#000000",
           buttonDownBottomBackgroundColor: "#FFFFFF",
           buttonDownTopBackgroundColor: "#FFFFFF",
           listTextSelectedColor: "#000000",
           listTextRollOverColor: "#333333",
           listRollOverColor: "#DDDDDD",
           listDownColor: "#EEEEEE",
           listSelectedUpColor: "#EEEEEE",
           listSelectedRollOverColor: "#D2D2D2",
           listUnuploadedColor: "#777777",
           listUploadedColor: "#FFFFFF",
           progressBarLeftColor: "#BBBBBB",
           progressBarRightColor: "#AAAAAA",
           progressBarLeftBorderColor: "#E1E1E1",
           progressBarRightBorderColor: "#E1E1E1",
           textColor: "#FFFFFF"
         };
         swfobject.embedSWF("/flashuploader/ElementITMultiPowUpload2.1.swf", "MultiPowUpload_holder", "380", "270", "9.0.0", "/flashuploader/expressInstall.swf", flashvars, params, attributes);

     </script></td>
   </tr>
</table>
</div>
</body>

感谢您的帮助！

Answer 1

我认为你的代码中有一个非常基本的错误（uploadfile.php）...你试图从$ _REQUEST错误的参数中检索..

从HTML传递隐藏文件作为“uploadscript”，你试图获得$ _REQUEST [“fileType”]＆amp; $ _REQUEST [“memberId”]不退出..（我不知道你是如何得到memberID，除非它以某种方式存在于POST中......

$uploaddir=realpath(dirname(__FILE__) . '/../../../memberimages/') . '/'.$_REQUEST["memberId"].'/My_Files/'.$_REQUEST["fileType"].'/';

要么，

（首选）在uploadfile.php中将它们作为您想要的单独参数发送或者
接收$ _REQUEST ['uploadscript']然后爆炸并继续工作......（noob方式）

另外，你的HIDDEN字段是如何在FORM标签之外的!!

<input name="uploadscript" id="uploadscript" type="hidden" value="/flashuploader/FileProcessingScripts/PHP/uploadfiles.php?memberId=43&fileType=Video" />

希望这很有帮助。

Answer 2

我通过将URL设置为一个参数来解决这个问题。我将它传递（在验证它只是字符串和可接受的数据之后）作为uploadfiles.php的一个参数。出于某种原因，php不喜欢多个参数。

无法在PHP中传递param

2 个答案: