我正在使用Spring MVC(3.2.2.RELEASE)和Spring Security(3.2.2.RELEASE)。
我尝试使用Spring安全性进行基本登录,但每次收到异常时都会触发HTTP状态405 - 请求方法' POST'不支持'。我已经尝试过搜索类似的问题,但我找不到任何解决方案。
以下是我的代码:
的login.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
</head>
<body>
<c:if test="${not empty error}">
<div>
<p style="color: red;">${error}</p>
</div>
</c:if>
<c:if test="${not empty message}">
<div>
<p style="color: red;">${message}</p>
</div>
</c:if>
<c:url var="loginUrl" value="/login" />
<form action="${loginUrl}" method="post">
<div>
<table>
<tr>
<td><label for="username">Email</label></td>
<td><input type="text" id="nombre" name="nombre" placeholder="Enter Name" required></td>
</tr>
<tr>
<td><label for="password">Password</label></td>
<td><input type="password" id="password" name="password" placeholder="Enter Password" required></td>
</tr>
</table>
</div>
<input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}" />
<div>
<input type="submit" value="Log In">
</div>
</form>
</body>
</html>
SecurityConfig.java
package com.bitacora.config;
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests()
.antMatchers("/login").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login").defaultSuccessUrl("/bitacora")
.failureUrl("/login?error")
.usernameParameter("nombre").passwordParameter("password")
.and()
.logout()
.logoutSuccessUrl("/login?logout").permitAll()
.and()
.csrf();
}
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
auth
.inMemoryAuthentication()
.withUser("user").password("123").roles("USER", "ADMIN");
}
}
MvcWebApplicationInitializer.java
package com.it2.config.core;
public class MvcWebApplicationInitializer extends
AbstractAnnotationConfigDispatcherServletInitializer {
@Override
protected Class<?>[] getRootConfigClasses() {
return new Class[] { SecurityConfig.class };
}
@Override
protected Class<?>[] getServletConfigClasses() {
return null;
}
@Override
protected String[] getServletMappings() {
return new String[] { "/" };
}
}
SecurityWebApplicationInitializer.java
package com.bitacora.config.core;
public class SecurityWebApplicationInitializer extends
AbstractSecurityWebApplicationInitializer {
public SecurityWebApplicationInitializer() {
super(SecurityConfig.class);
}
}
LoginController.java
package com.bitacora.controller;
@Controller
public class LoginController extends HttpServlet {
@RequestMapping(value = "/login", method = RequestMethod.GET)
public ModelAndView loginPage(@RequestParam(value = "error",required = false) String error) {
ModelAndView model = new ModelAndView();
if (error != null) {
model.addObject("error", "Invalid Email OR Password");
}
model.setViewName("login");
return model;
}
}
Bitácora酒店-servlet.xml中
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.bitacora" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
<mvc:resources mapping="/img/**" location="/img/" />
<mvc:resources mapping="/css/**" location="/css/" />
<mvc:annotation-driven />
<import resource="classpath://Spring.xml"/>
</beans>
的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>BitacoraWEB</display-name>
<welcome-file-list>
<welcome-file>login.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>bitacora</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>bitacora</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
答案 0 :(得分:0)
因为您的服务(Controller)登录操作是一个get操作,但您的UI(视图)正在发送一个帖子请求
@RequestMapping(value = "/login", method = RequestMethod.GET)
你应该把它改成
@RequestMapping(value = "/login", method = RequestMethod.POST)
保持您的UI(视图)不变(使用method =“post”)
<form:form id="loginForm" method="post" action="${loginUrl}"
modelAttribute="loginBean">
答案 1 :(得分:-1)
您要将登录信息发布到when you are removing data from array call notifyDataSetChanged();
,但Spring Security 3.2 中的默认登录处理网址为/login
。
表单更改:
/j_spring_security_check
或设置登录处理URL:
<c:url var="loginUrl" value="/j_spring_security_check" />