无法在App启动时调用广播接收器

时间:2016-04-26 14:41:41

标签: android xamarin android-broadcastreceiver

您好我一直在尝试创建一个广播接收器,但我无法调用它,即从应用程序启动启动它在这里是我的代码请告诉我,是否缺少某些东西是我现在尝试的东西< / p>

<?xml version="1.0" encoding="utf-8"?>
 <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.testing.broacast" android:versionCode="1" android:versionName="1.0" android:installLocation="auto">
<uses-sdk android:minSdkVersion="16" />
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
<application android:label="App4"></application>
<receiver android:name=".Broadcast">
    <intent-filter>
        <action android:name="android.intent.action.BOOT_COMPLETED" />
    </intent-filter>
</receiver>
 </manifest>

这是我的广播接收器

[BroadcastReceiver]
[IntentFilter(new[] { Intent.ActionBootCompleted })]


public class Broadcast : BroadcastReceiver
{
    public override void OnReceive(Context context,Intent intent)
    {

            Toast.MakeText(context, "Hello", ToastLength.Long).Show();
            // Create your application here}

    }
}

1 个答案:

答案 0 :(得分:1)

这就是它在我的设备上的工作方式

[BroadcastReceiver(Enabled = true)]
[IntentFilter(new[] { Intent.ActionBootCompleted })]
public class Broadcast : BroadcastReceiver
{
    public override void OnReceive(Context context, Intent intent)
    {
        Toast.MakeText(context, "Hello", ToastLength.Long).Show();
    }
}

差异为[BroadcastReceiver(Enabled = true)]

此外,我无需将receiver标记放入AndroidManifest.xml