Question

您好我正在尝试创建一个活动，其中SearchView用于搜索Android手机中的联系人列表，并点击建议或按＆＃34;输入＆＃34;键盘上的按钮，同一个联系人显示在列表视图中，只显示联系人姓名。但是，我遇到了两个问题：

关于建议单击，联系人将显示在列表视图中，但当我进行另一次搜索时，同一行将替换为新联系人。 CursorAdapter没有形成任何列表。
按下＆＃34;输入＆＃34;按钮，光标变为＆＃34; null＆＃34;值。

这是我的代码：

public class FamilyAndFriends extends AppCompatActivity {

    Typeface mytypeface1;
    SearchView searchView;
    ListView contactlist;
    CursorAdapter nameAdapter;
    ContentResolver cr;

    public static final String projection[] = {ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME, ContactsContract.Contacts.LOOKUP_KEY};

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_family_and_friends);

        TextView textView = (TextView) findViewById(R.id.textView9);
        mytypeface1 = Typeface.createFromAsset(getAssets(), "Roboto-Light.ttf");
        textView.setTypeface(mytypeface1);

        Toolbar toolbar = (Toolbar) findViewById(R.id.app_bar);
        toolbar.setTitle("Friends & Family");
        setSupportActionBar(toolbar);

        getSupportActionBar().setHomeButtonEnabled(true);
        getSupportActionBar().setDisplayHomeAsUpEnabled(true);

        searchView = (SearchView) findViewById(R.id.searchView);
        setupSearchView();

        contactlist = (ListView) findViewById(R.id.listView);
        cr = getContentResolver();


    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {

        getMenuInflater().inflate(R.menu.menu_user_info, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected(MenuItem item) {
        int id = item.getItemId();

        switch (id) {
            case android.R.id.home:
                NavUtils.navigateUpFromSameTask(this);
                break;
            case R.id.next:
                startActivity(new Intent(this, Settings.class));
                break;
        }
        return true;
    }

    private void setupSearchView() {

        SearchManager searchManager = (SearchManager) getSystemService(Context.SEARCH_SERVICE);
        SearchableInfo searchableInfo = searchManager.getSearchableInfo(getComponentName());
        searchView.setSearchableInfo(searchableInfo);
        searchView.setQueryRefinementEnabled(true);
        searchView.setIconifiedByDefault(false);

    }


    @Override
    protected void onNewIntent(Intent intent) {

        setIntent(intent);
        handleIntent();
    }

    private void handleIntent() {

        Intent intent = getIntent();

        if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
            String query = intent.getStringExtra(SearchManager.QUERY);
            dosearch(query);

        } else if (ContactsContract.Intents.SEARCH_SUGGESTION_CLICKED.equals(intent.getAction())) {
            Uri nameUri = intent.getData();
            String suggested_contact = String.valueOf(nameUri);
            dosearch(suggested_contact);


        }
    }

    private void dosearch(final String query) {

        Cursor nameCursor = cr.query(Uri.parse(query),projection,null,null,null);

        nameCursor.moveToFirst();

        int colindex = nameCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
        final String result = nameCursor.getString(colindex);

        nameAdapter = new CursorAdapter(FamilyAndFriends.this, nameCursor, 0) {
            @Override
            public View newView(Context context, Cursor cursor, ViewGroup parent) {

                return LayoutInflater.from(context).inflate(R.layout.contact_listview, parent, false);
            }

            @Override
            public void bindView(View view, Context context, Cursor cursor) {
                TextView nameContact = (TextView) view.findViewById(R.id.contact_name);
                nameContact.setText(result);
                nameContact.setTypeface(mytypeface1);
            }
        };
        contactlist.setAdapter(nameAdapter);
        nameCursor.close();
    }

}

任何人都可以帮我找到所需的清单吗???请帮助。

使用Contact Provider：Cursor具有null值

0 个答案: