Question

我有一个addpost.php，它有一个将博客文章提交到mysql数据库的表单。表格是：

blog_post_cats

+--------+------------------+------+-----+---------+----------------+
| Field  | Type             | Null | Key | Default | Extra          |
+--------+------------------+------+-----+---------+----------------+
| id     | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| postID | int(11)          | YES  |     | NULL    |                |
| catID  | int(11)          | YES  |     | NULL    |                |
+--------+------------------+------+-----+---------+----------------+

blog_posts_seo

+-----------+------------------+------+-----+---------+----------------+
| Field     | Type             | Null | Key | Default | Extra          |
+-----------+------------------+------+-----+---------+----------------+
| postID    | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| postTitle | varchar(255)     | YES  |     | NULL    |                |
| postDesc  | text             | YES  |     | NULL    |                |
| postCont  | text             | YES  |     | NULL    |                |
| postDate  | datetime         | YES  |     | NULL    |                |
+-----------+------------------+------+-----+---------+----------------+

blog_cats

+----------+------------------+------+-----+---------+----------------+
| Field    | Type             | Null | Key | Default | Extra          |
+----------+------------------+------+-----+---------+----------------+
| catID    | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| catTitle | varchar(255)     | YES  |     | NULL    |                |
+----------+------------------+------+-----+---------+----------------+

当用户提交表单时，帖子标题，内容，描述会发布到blog_posts_seo表，但所选类别也会将catID和postID传递给blog_post_cats表。下面是表单字段的示例。此外，如何通过查询blog_cats表显示类别名称和复选框：

<form action='' method='post'>

    <p><label>Title</label><br />
    <input type='text' name='postTitle' value='<?php if(isset($error)){ echo $_POST['postTitle'];}?>'></p>

    <p><label>Description</label><br />
    <textarea name='postDesc' cols='60' rows='10'><?php if(isset($error)){ echo $_POST['postDesc'];}?></textarea></p>

    <p><label>Content</label><br />
    <textarea name='postCont' cols='60' rows='10'><?php if(isset($error)){ echo $_POST['postCont'];}?></textarea></p>

    <fieldset>
        <legend>Categories</legend>

        <?php   

        $stmt2 = $db->query('SELECT catID, catTitle FROM blog_cats ORDER BY catTitle');
        while($row2 = $stmt2->fetch()){

            if(isset($_POST['catID'])){

                if(in_array($row2['catID'], $_POST['catID'])){
                   $checked="checked='checked' ";
                }else{
                   $checked = null;
                }
            }

            echo "<input type='checkbox' name='catID[]' value='".$row2['catID']."' $checked> ".$row2['catTitle']."<br />";
        }

        ?>

    </fieldset>

    <p><input type='submit' name='submit' value='Submit'></p>

</form>

因此，如果按下提交按钮，则执行insert语句：

try {


                //insert into database
                $stmt = $db->prepare('INSERT INTO blog_posts_seo (postTitle,postDesc,postCont,postDate) VALUES (:postTitle, :postDesc, :postCont, :postDate)') ;
                $stmt->execute(array(
                    ':postTitle' => $postTitle,
                    ':postDesc' => $postDesc,
                    ':postCont' => $postCont,
                    ':postDate' => date('Y-m-d H:i:s')
                ));
                $postID = $db->lastInsertId();

                //add categories
                if(is_array($catID)){
                    foreach($_POST['catID'] as $catID){
                        $stmt = $db->prepare('INSERT INTO blog_post_cats (postID,catID)VALUES(:postID,:catID)');
                        $stmt->execute(array(
                            ':postID' => $postID,
                            ':catID' => $catID
                        ));
                    }
                }

                //redirect to index page
                header('Location: index.php?action=added');
                exit;

实际发生的事情是将NOTHING传递给blog_post_cats表!!所以我不确定会出现什么问题？

我认为插入语句对于将catID和postID插入blog_post_cats表是正确的，所以我怀疑以下是错误的：

<fieldset>
            <legend>Categories</legend>

            <?php   

            $stmt2 = $db->query('SELECT catID, catTitle FROM blog_cats ORDER BY catTitle');
            while($row2 = $stmt2->fetch()){

                if(isset($_POST['catID'])){

                    if(in_array($row2['catID'], $_POST['catID'])){
                       $checked="checked='checked' ";
                    }else{
                       $checked = null;
                    }
                }

                echo "<input type='checkbox' name='catID[]' value='".$row2['catID']."' $checked> ".$row2['catTitle']."<br />";
            }

            ?>

        </fieldset>

任何帮助表示感谢。

Answer 1

经过大量测试后，我发现了为什么catID和postID没有插入的问题......

if(isset($_POST['submit'])){

        $_POST = array_map( 'stripslashes', $_POST );

        //collect form data
        extract($_POST);

我没有在我的问题中包含此代码，我发现如果我注释掉了：

/*$_POST = array_map( 'stripslashes', $_POST );

            //collect form data
            extract($_POST);*/

... catID和postID正确插入数据库。

似乎我将$ _POST数组的值发送到stripslashes函数，但它阻止了数据插入到数据库中。

PHP记录未插入MySql博客类别表

1 个答案: