Question

我无法理解控件是如何从＆＃34; Expl Thread＆＃34;输出语句到＆＃34;主线程＆＃34;输出声明。

package com.myjava.threads;

class MyRunnableThread implements Runnable {
    public static int myCount = 0;

    public MyRunnableThread() {
    }

    public void run() {
        while (MyRunnableThread.myCount <= 10) {
            try {
                System.out.println("Expl Thread: " + (++MyRunnableThread.myCount));
                Thread.sleep(100);
            } catch (InterruptedException iex) {
                System.out.println("Exception in thread: " + iex.getMessage());
            }
        }
    }
}

public class RunMyThread {
    public static void main(String a[]) {
        System.out.println("Starting Main Thread...");
        MyRunnableThread mrt = new MyRunnableThread();
        Thread t = new Thread(mrt);
        t.start();
        while (MyRunnableThread.myCount <= 10) {
            try {
                System.out.println("Main Thread: " + (++MyRunnableThread.myCount));
                Thread.sleep(100);
            } catch (InterruptedException iex) {
                System.out.println("Exception in main thread: " + iex.getMessage());
            }
        }
        System.out.println("End of Main Thread...");
    }
}



The output is:

启动主线程......

Main Thread: 1
Expl Thread: 2
Main Thread: 3
Expl Thread: 4
Main Thread: 5
Expl Thread: 6
Main Thread: 7
Expl Thread: 8
Main Thread: 9
Expl Thread: 10
Main Thread: 11
End of Main Thread...

Answer 1

控件如何从“Expl Thread”输出语句转换为“Main Thread”输出语句。

未传递控制权。相反，每个线程都在调用

Thread.sleep(100);

由于这是相同的时间，他们轮流。将其中一个更改为sleep(50)，您将看到一个打印消息的速度是原来的两倍。

Answer 2

没有传输的控件......线程每100毫秒独立打印到控制台。由于时间是相同的，所以看起来他们轮流＆＃34;但是＆＃34;首先＆＃34;不确定。

更改其中一个Thread.sleep(100);值，您会看到一个将比另一个更长/更短来打印。

Answer 3

这是线程调度程序决定的内容。当您启动线程时，它将与已经存在的其他线程并行运行。它由线程调度程序决定分配给每个线程的顺序和时间。

无法保证执行顺序。

有人可以解释这个代码，它与线程有关

3 个答案: