Question

我正在寻找一种从一个PHP表单向两个mySQL数据库提交数据的方法。

我希望所有文本信息都转到一个数据库，所有图像转到另一个数据库。

我该怎么做呢？（参见下面附带的代码，距离我希望的地方还很远）：

<?php
/*
Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password)
*/
$link = mysqli_connect("****", "****", "****", "****");

// Check connection
if($link === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
}

// Escape user inputs for security
$title = mysqli_real_escape_string($link, $_POST['title']);
$price = mysqli_real_escape_string($link, $_POST['price']);
$sqm = mysqli_real_escape_string($link, $_POST['sqm']);
$sqm_land = mysqli_real_escape_string($link, $_POST['sqm_land']);
$type = mysqli_real_escape_string($link, $_POST['type']);
$area = mysqli_real_escape_string($link, $_POST['area']);
$location = mysqli_real_escape_string($link, $_POST['location']);
$bedroom = mysqli_real_escape_string($link, $_POST['bedroom']);
$terrace = mysqli_real_escape_string($link, $_POST['terrace']);
$orientation = mysqli_real_escape_string($link, $_POST['orientation']);
$water = mysqli_real_escape_string($link, $_POST['water']);
$seaview = mysqli_real_escape_string($link, $_POST['seaview']);
$pool = mysqli_real_escape_string($link, $_POST['pool']);
$ownerinfo = mysqli_real_escape_string($link, $_POST['ownerinfo']);
$gaddress = mysqli_real_escape_string($link, $_POST['gaddress']);
$description = mysqli_real_escape_string($link, $_POST['description']);




// attempt insert query execution
$sql = "INSERT INTO property (title, price, sqm, sqm_land, type, area, location, bedroom, terrace, orientation, water, seaview, pool, ownerinfo, gaddress, description) VALUES 
('$title', '$price', '$sqm', '$sqm_land', '$type', '$area', '$location', '$bedroom', '$terrace', '$orientation', '$water', '$seaview', '$pool', '$ownerinfo', '$gaddress', '$description' )";
if(mysqli_query($link, $sql)){
    echo "Records added successfully.";
} else{
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}




// close connection
mysqli_close($link);
?>

对此我们将不胜感激。

Answer 1

完成另一个后，您可以更改数据库：

mysqli_select_db($link,"new_db_to_choose");

Answer 2

只需创建两个mysql连接：

$ link1和$ link2

然后使用两个连接调用mysqli_query函数：

mysqli_query($link1, $sql);
mysqli_query($link2, $sql);

Answer 3

您可以像这样建立多个数据库连接

$text_db = mysqli_connect("****", "****", "****", "****");

$img_db = mysqli_connect("****", "****", "****", "****");

然后，您必须在运行的任何后续查询中使用正确的句柄。

mysqli_query($text_db, 'the query for the test parts')

mysqli_query($img_db, 'the query for the images')

两个mySQL数据库到一个PHP表单

3 个答案: