Question

我在php中编写REST apis而不使用任何框架。我可以使用字符串数据作为参数调用apis，但是当我使用JSON对象作为参数调用url时会出现问题。

- 我的.htaccess文件如下：

# Turn rewrite engine on
Options +FollowSymlinks
RewriteEngine on


# map neat URL to internal URL
RewriteRule ^get/([a-z0-9\-]+)/$    RestController.php?box=$1 [nc,qsa]

RewriteRule ^addinbox/([a-z0-9\-]+)/$   RestController.php?emailObj=$1&mode=addinbox [nc,qsa]

我正在使用jQuery进行ajax调用：

-ajax电话：

var emailObj = {
                "name": "Mathew Murddock",
                "receiver": receiver,
                "sender": "daredevil@marvel.com",
                "subject": subject,
                "content": body,
                "time_stamp": time_stamp
            };
            var objToSend = JSON.stringify(emailObj);
            $.ajax({ 
               type: 'GET',
               contentType: 'application/json; charset=utf-8',
               url: "http://localhost/emailServer/addinbox/",
               dataType: 'json',
               data: objToSend+'/',
               success: function(response){
                    console.log(response);
               }
            });

但是会返回此错误：

XMLHttpRequest cannot load http://localhost/emailServer/addinbox/?{%22name%22:%22Mathew%20Murddock%22,…%22This%20is%20%20some%20dummy%20text.%22,%22time_stamp%22:%2212:35:0%22}/. Response to preflight request doesn't pass access control check: No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'null' is therefore not allowed access.

虽然我在服务器端允许交叉来源： -RestController.php

<?php
    header('Access-Control-Allow-Origin: *');
    //Remaining code

我在ajax调用时获得的URL是：

http://localhost/emailServer/addinbox/?{%22name%22:%22Mathew%20Murddock%22,%22sender%22:%22daredevil@marvel.com%22,%22subject%22:%22This%20is%20a%20mail%22,%22content%22:%22This%20is%20%20some%20dummy%20text.%22,%22time_stamp%22:%2212:35:0%22}/

我是否以错误的方式重写了网址？

Answer 1

（[a-z0-9 - ] +）匹配小写字母，数字和＆＃34; - ＆＃34;没有其他所以你不会匹配你的json，也考虑停止发送json得到所有。这是一个不好的做法为了给你打电话，你向我们展示了你的api实际上需要一个POST

Answer 2

我认为您不需要使用JSON.stringify（emailObj）;

contentType: 'application/json; charset=utf-8'
// this line says you need to  send json file but you are sending stirng file

我认为你根本不需要在这里使用JSON.stringify或json_decode。只是做：

data : {
            "name": "Mathew Murddock",
            "receiver": receiver,
            "sender": "daredevil@marvel.com",
            "subject": subject,
            "content": body,
            "time_stamp": time_stamp
        },

并在php中

$name=$_POST['name'];

请告诉我，如果不适合你？

重写url接受json数据php（请求方法：GET）

2 个答案: