我有一些包提供了一些tcp连接的工作,基本上类似于:
package connpool
import (
"io/ioutil"
"net/http"
)
type ConnPool struct{}
func (pool *ConnPool) GetConn() Conn {
return Conn{}
}
func (pool *ConnPool) ReleaseConnection(conn Conn) {
}
type Conn struct{}
func (c Conn) FetchUrl(url string) ([]byte, error) {
req, err := http.NewRequest("GET", url, nil)
if err != nil {
return []byte{}, err
}
client := &http.Client{}
resp, _ := client.Do(req)
defer resp.Body.Close()
body, _ := ioutil.ReadAll(resp.Body)
return body, nil
}
然后我尝试在另一个包中使用它,但是通过接口包装它,因为我想在测试环境中用假connpool替换这个包
package main
import (
"connpool"
"fmt"
)
func onlyDependencyOnConnPool() *connpool.ConnPool {
return &connpool.ConnPool{}
}
type ConnPoolInterface interface {
GetConn() ConnInterface
ReleaseConnection(ConnInterface)
}
type ConnInterface interface {
FetchUrl(string) ([]byte, error)
}
type Fetcher struct{}
func (f Fetcher) Fetch(cPool ConnPoolInterface) error {
conn := cPool.GetConn()
defer cPool.ReleaseConnection(conn)
body, err := conn.FetchUrl("http://localhost:9200")
fmt.Println("body: ", string(body))
return err
}
func main() {
pool := onlyDependencyOnConnPool()
f := Fetcher{}
f.Fetch(pool)
}
但它会在编译时返回错误:
./main.go:34: cannot use pool (type *connpool.ConnPool) as type ConnPoolInterface in argument to f.Fetch:
*connpool.ConnPool does not implement ConnPoolInterface (wrong type for GetConn method)
have GetConn() connpool.Conn
want GetConn() ConnInterface
是否可以通过接口包装此依赖项而不在每个文件中使用connpool导入?
我只需要在我的测试环境中模拟http请求,就像这样(如果我将在connpool包中实现接口,我将不得不实现其中的每个模拟结构,它看起来像某种混乱):
package main
import(
"testing"
)
type FakeConnPool struct{}
func (pool *FakeConnPool) GetConn() FakeConn {
return FakeConn{}
}
func (pool *FakeConnPool) ReleaseConnection(conn FakeConn) {
}
type FakeConn struct{}
func (c FakeConn) FetchUrl(url string) ([]byte, error) {
println(url)
body := []byte(`{"status" : 200}`)
return body, nil
}
func changeDependency() ConnPoolInterface {
return &FakeConnPool{}
}
func TestBaz(t *testing.T) {
pool := changeDependency()
f := Fetcher{}
err := f.Fetch(pool)
if err != nil {
t.Errorf("error")
}
}
答案 0 :(得分:0)
首先,只需将GetConn
的声明稍微更改为以下内容:
func (pool *ConnPool) GetConn() ConnInterface { // Conn -> ConnInterface
return Conn{}
}
这应该符合ConnPoolInterface
的界面。您可能需要稍微重新排列代码以避免循环依赖。