SELECT t1.name
FROM title t1
WHERE t1.rating >
(SELECT t2.rating FROM title t2 GROUP BY t2.genre
HAVING t1.genre = t2.genre AND t2.is_movie = 0);
给我一个无效的标识符错误。看起来在嵌套子查询中无法识别表t1。谁知道我做错了什么?
答案 0 :(得分:0)
您可以使用连接在同一桌面上的内联视图以这种方式重新编写查询。
SELECT t1.name
FROM title t1,(select genre,avg(rating) as rating
from title
where is_movie = 0
group by genre) t2
WHERE
t1.genre = t2.genre
AND t1.is_movie = 0
AND t1.rating > t2.rating