Question

我正在尝试将django id存储到列表中。但它将两位数字存储为单独的两位数字。例如，它将10存储为1和0.它将值存储为unicode字符。任何人都可以帮助我

   def practice_view(request, id=None):
        msg = ''
        if request.method == 'POST':
            questions = request.POST.get('Que');
            list = [];
            result = [];
            total = 0;
            for i in questions:
                if i.isdigit():
                    list.append(i)
                total = total + 1;
    During debugging this is what it displays
    Que=u'[6, 7, 8, 9, 10, 11, 12]'
    questions=u'[6, 7, 8, 9, 10, 11, 12]'
    list=[u'6', u'7', u'8', u'9', u'1', u'0', u'1', u'1', u'1', u'2']

Answer 1

像这样更改你的代码，

import ast
def practice_view(request, id=None):
    msg = ''
    if request.method == 'POST':
        questions = ast.literal_eval(request.POST.get('Que'))
        lst = [];
        result = [];
        total = 0;
        for i in questions:
            if type(i) == 'int':
                lst.append(i)
            total = total + 1;

由于查询字符串param Que的值是一个字符串，python应该迭代字符串中存在的每个字符。

将django id添加到列表中

1 个答案: