我写了以下代码,这些代码用于Ajax
的消息功能。
当我填写
<script>alert("Django+Ajax");</script>
在表单中提交,警报出现在我的浏览器上。 我想逃避输出,但我不知道该怎么做。 你能给我一些建议吗?
message.html
<html>
<head>
<style type="text/css">
div#message_form {
display: none;
margin: 25px;
padding: 25px;
background: #eee;
width: 200px;
height: 180px;
}
</style>
</head>
<body>
<input type="button" id="message" value="message"> <br />
<div id="message_form">
<form id="post_message" method="POST" action="">
{% csrf_token %}
title: {{ form.title }} <br />
body: {{ form.body }} <br />
<input type="submit" value="send">
<input type="reset" value="reset">
</form>
</div>
<div id="get_title"></div>
<div id="get_body"></div>
{% load staticfiles %}
<script type="text/javascript" src="{% static "myapp/js/jQuery.js" %}"></script>
<script type="text/javascript" src="{% static "myapp/js/django_ajax.js" %}"></script>
<script type="text/javascript">
$(function() {
$('#message').on('click', function() {
$('#message_form').slideToggle();
});
$('#message_form').submit(function(e) {
e.preventDefault();
var url = location.href;
var arr = url.split('/');
$.ajax({
type: 'POST',
url: '/myapp/deal_message/',
dataType: 'json',
data: {
'title': $('#title').val(),
'body': $('#body').val(),
'target_id': arr[arr.length-2],
},
success: function(data, dataType) {
$('#get_title').append(data.title); <!-- ### HERE ### -->
$('#get_body').append(data.body); <!-- ### HERE ### -->
$('#post_message')[0].reset();
},
error: function(XMLHttpRequest, textStatus, errorThrown) {
alert('Error: ' + errorThrown);
},
});
return false;
});
});
</script>
</body>
</html>
forms.py
class Message(forms.ModelForm):
class Meta:
model = Message
fields = ('title', 'body',)
widgets = {
'title': forms.TextInput(attrs={'id': 'title', 'placeholder': 'message title'}),
'body': forms.Textarea(attrs={'rows': 4, 'cols': 18, 'id': 'body', 'placeholder': 'message body'}),
}
labels = {field:field for field in fields}
help_texts = {}
error_messages = {}
views.py
#@login_required(login_url='/')
def message(request, owner_id):
errors = ""
from myapp.forms import Message
view = {
'errors': errors,
'form': Message,
}
template = 'myapp/message/message.html'
return render(request, template, view)
def deal_message(request):
u""" """
#import pdb; pdb.set_trace()
errors = ""
sender_id = [request.user.user_id if isinstance(request.user.user_id, int) else 0].pop()
try:
target_id = int(request.POST['target_id'])
except ValueError as ve:
errors = ve
def chat_exist(sender_id, target_id):
# 1 on 1
from myapp.models import Chat
from myapp.models import Chat_Member
try:
sender_chats = Chat_Member.objects.filter(user_id=sender_id).filter(chat__type=0)
target_chats = Chat_Member.objects.filter(user_id=target_id).filter(chat__type=0)
cid = set([o.chat_id for o in sender_chats]) & set([o.chat_id for o in target_chats])
if len(cid) == 0:
new_chat = Chat()
new_chat.type = 0
new_chat.save()
#new_chat.member = Chat_Member()
c1 = Chat_Member(chat_id=new_chat.chat_id, user_id=sender_id)
c2 = Chat_Member(chat_id=new_chat.chat_id, user_id=target_id)
c1.save()
c2.save()
return new_chat.chat_id
else:
if len(cid) != 1:
raise
else:
return cid.pop()
except:
return 0
chat_id = int(chat_exist(sender_id, target_id))
res = {}
from myapp.forms import Message
formset = Message
if request.method == 'POST':
form = formset(request.POST)
if form.is_valid():
try:
res['title'] = form.cleaned_data['title']
res['body'] = form.cleaned_data['body']
res = json.dumps(res)
from myapp.models import Chat
from myapp.models import Message
new_message = Message()
new_message.user_id = sender_id
new_message.chat_id = chat_id
new_message.title = form.cleaned_data['title']
new_message.body = form.cleaned_data['body']
new_message.save()
new_chat = Chat(chat_id=chat_id)
new_chat.last_message = form.cleaned_data['body'][:30]
new_chat.save()
except:
errors = "DB Error"
else:
errors = ""
return HttpResponse(res, content_type="application/json; charset=UTF-8")
jQuery
:2.2.0
,Django
:1.9.1
,Python
:3.5.1
答案 0 :(得分:4)
您需要转义您在JSON对象中输出的HTML。通常Django会在常规响应中为您做到这一点,但是当您将其封装在JSON中时,它并不是那么直截了当。
在编码JSON之前使用escape
函数,如in this question所述,如下所示:
from django.utils.html import escape
# ...
res['title'] = escape(form.cleaned_data['title'])
res['body'] = escape(form.cleaned_data['body'])
res = json.dumps(res)
答案 1 :(得分:2)
有一种非常基本的方法来解决与表单相关的任何类型的XSS,无论何时提交它只是验证特殊字符,如&lt; &GT; ()+等或尝试逃避XSS字符。更多详情here