Question

我想在文件中用第一行（注意sed -e '1s/ /_/g' head_test.csv中的1）替换没有下划线和括号的空格。

这是我正在使用的文件：

$ head -n 1  head_test.csv
"Rec Open Date","MSISDN","IMEI","Data Volume (Bytes)","Device Manufacturer","Device Model","Product Description"

这就是我使用sed实现它的方式

$ sed -e '1s/ /_/g' head_test.csv |  sed -e '1s/(//g' | sed -e '1s/)//g' | head -n 1
"Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model","Product_Description"

但我无法使用-i.bak选项覆盖现有文件。任何人都可以使用-i选项建议我如何做到这一点。

Answer 1

我建议将所有3个bodyParser: (function() { var opts = { limit: '50mb' }; var fn; // Default to built-in bodyParser: fn = require('skipper'); return fn(opts); }),调用合并为1，然后添加sed以在-i.bak命令之前创建名为data.bak的备份文件执行，也没有必要创建一个只有第一行的文件，即管道末端不需要sed和最后head_test.csv命令：

head

$ ls data* data $ cat data "Rec Open Date","MSISDN","IMEI","Data Volume (Bytes)","Device Manufacturer","Device Model","Product Description" abcd xyz $ sed -i.bak -e '1s/\s/_/g' -e '1s/(//g' -e '1s/)//g' data $ cat data "Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model","Product_Description" abcd xyz $ cat data.bak "Rec Open Date","MSISDN","IMEI","Data Volume (Bytes)","Device Manufacturer","Device Model","Product Description" abcd xyz $表示就地编辑，即-i执行文件数据上的所有命令，并保留文件中的所有更改，从而有效地更改文件内容

sed 1st创建文件的备份副本：-i.bak，然后对filename.bak进行更改

使用sed查找字符串并在某行上替换它+使用-i.bak

1 个答案: