Question

您好我想在视图中使用简单的复杂数组。

然而，我有点陷入困境

请看看我对阵列的误解

我希望这个数组简单

'collection' => [
    (int) 0 => [
        'type' => 'col',
        'name' => '2016 F/W',
        'url' => 'blablabla'
    ],
    (int) 1 => [
        'type' => 'col',
        'name' => '2015 F/W',
        'url' => 'blablabla'
    ],
    (int) 2 => [
        'type' => 'project',
        'name' => '2015 F/W',
        'url' => 'blablabla'
    ]
]

我希望这个数组像这样

[
(int) 0 => [
    'type' => 'col',
    'type2' => [
        (int) 0 => [
            'name' => '2016 F/W',
            'image' => [
                (int) 0 => [
                    'url' => null
                ],
                (int) 1 => [
                    'url' => null
                ]
            ]
        ],
        (int) 1 => [
            'name' => '2015 F/W',
            'image' => [
                (int) 0 => [
                    'url' => null
                ]
            ]
        ]
    ]
],
(int) 1 => [
    'type' => 'project',
    'type2' => [
        (int) 0 => [
            'name' => '2015 F/W',
            'image' => [
                (int) 0 => [
                    'url' => null
                ]
            ]
        ],
    ]
]

请帮助!!我快要疯了!!!!

Answer 1

我得说结果数组看起来不是很有用。由于关于此任务目标的信息不多，我只是提供了如何完成此任务......

    $arr = array(
        'collection' => array(
            array(
                'type' => 'col',
                'name' => '2016 fw',
                'url' => 'blabla1'
            ),
            array(
                'type' => 'col',
                'name' => '2015 F/W',
                'url' => 'blabla2'
            ),
            array(
                'type' => 'project',
                'name' => '2015 F/W',
                'url' => 'blabla_project'
            ),

        ),
    );

    // $types array will hold a list of all types. type in this 
    // example is 'col' and 'project'. 
    // we will use $types to find if type X was already added to the 
    // result array.
    $types = array();

    // Every type X will be in the result array in key K, So $typesMap
    // will map between the type to the key in the result array.
    // Example: type X is located in the result array under key K
    // So I can find the type X data by looking at the 
    // $resultArr[K]
    $typesMap = array();
    $typeIndx = 0;

    // This is the result array.
    $resultArr = array();

    // run over all collections
    foreach($arr['collection'] as $collection){

        // get the current type. e.g 'col'
        $type = $collection['type'];

        // Search the $types array for 'col' to see if it was defined
        // already.
        if(!in_array($type, $types)) {
            // if it wasn't defined then define it now:

            // add it to the $types array so that we can find it on
            // the next run.
            $types[] = $type;

            // define the key (K) that it will be in the $resultArr
            $typesMap[$type] = $typeIndx;

            // Create the 'col' key in the result array.
            $resultArr[$typeIndx] = array('type' => $type, 'type2' => array());
            $typeIndx++;
        }

        // get the key for type $type.
        // remember? I can use the $typesMap to find the type's index
        // in the result array.
        $currentIndx = $typesMap[$type];

        // add the extra data to the 'type2' (not a very good name for
        // this)
        $resultArr[$currentIndx]['type2'][] = array(
            'name' => $collection['name'],
            'image' => $collection['url']
        );

    }

我真的不了解结果数组的url部分..

PHP如何使复杂的大型数组变得简单

1 个答案: