Question

我对hibernate很新，我在一对一映射中面临问题。

我有两个Mysql表用户和userinfo。在用户表中存储用户的登录凭证，并且在userinfo中存储其信息（例如年龄，资格等）。用户表将Id作为主键，而用户的PK Id是userinfo表的外键。

以下是我的两个映射类：

@Entity
@Table(name="UserTable")
public class LoginDetailsModel {
@OneToOne(fetch = FetchType.LAZY, mappedBy = "loginDetailsModel", cascade = CascadeType.ALL)
@JoinColumn(name = "id")
private LICUserInfoModel userInfoModel;

@Id
@Column(name="ID")
@GeneratedValue(strategy=GenerationType.IDENTITY)
private int id;

@Column(name = "username")
private String username;

@Column(name = "passwd")
private String passwd;

@Column(name = "emailId")
private String emailId;

@Column(name = "userRole")
private String userRole;

/**
 * @return the id
 */
public int getId() {
    return id;
}

/**
 * @param id the id to set
 */
public void setId(int id) {
    this.id = id;
}

/**
 * @return the username
 */
public String getUsername() {
    return username;
}

/**
 * @param username the username to set
 */
public void setUsername(String username) {
    this.username = username;
}

/**
 * @return the passwd
 */
public String getPasswd() {
    return passwd;
}

/**
 * @param passwd the passwd to set
 */
public void setPasswd(String passwd) {
    this.passwd = passwd;
}

/**
 * @return the emailId
 */
public String getEmailId() {
    return emailId;
}

/**
 * @param emailId the emailId to set
 */
public void setEmailId(String emailId) {
    this.emailId = emailId;
}

/**
 * @return the userRole
 */
public String getUserRole() {
    return userRole;
}

/**
 * @param userRole the userRole to set
 */
public void setUserRole(String userRole) {
    this.userRole = userRole;
}

/**
 * @return the userInfoModel
 */
public LICUserInfoModel getUserInfoModel() {
    return userInfoModel;
}

/**
 * @param userInfoModel the userInfoModel to set
 */
public void setUserInfoModel(LICUserInfoModel userInfoModel) {
    this.userInfoModel = userInfoModel;
}

}

@Entity
@Table(name="UserInfo")
public class LICUserInfoModel {

private LoginDetailsModel loginDetailsModel;

@Id
@Column(name="userinfo_id")
@GeneratedValue(strategy=GenerationType.IDENTITY)
private int userinfo_id;

@GenericGenerator(name = "generator", strategy = "foreign", 
        parameters = @Parameter(name = "property", value = "loginDetailsModel"))
        @Id
        @GeneratedValue(generator = "generator")
        @Column(name = "ID", unique = true, nullable = false)
private int id;

@Column(name = "fullname")
private String fullname;

@Column(name = "qualification")
private String qualification;

@Column(name = "address")
private String address;

@Column(name = "gender")
private String gender;

@Column(name = "contact_no")
private long contact_no;

@Column(name = "contact_email")
private String contact_email;

@Column(name = "resume")
private String resume;

@Column(name = "dob")
private Date dob;   


/**
 * @return the userinfo_id
 */
public int getUserinfo_id() {
    return userinfo_id;
}

/**
 * @param userinfo_id the userinfo_id to set
 */
public void setUserinfo_id(int userinfo_id) {
    this.userinfo_id = userinfo_id;
}

/**
 * @return the id
 */
public int getId() {
    return id;
}

/**
 * @param id the id to set
 */
public void setId(int id) {
    this.id = id;
}
/**
 * @return the fullname
 */
public String getFullname() {
    return fullname;
}
/**
 * @param fullname the fullname to set
 */
public void setFullname(String fullname) {
    this.fullname = fullname;
}
/**
 * @return the qualification
 */
public String getQualification() {
    return qualification;
}
/**
 * @param qualification the qualification to set
 */
public void setQualification(String qualification) {
    this.qualification = qualification;
}
/**
 * @return the address
 */
public String getAddress() {
    return address;
}
/**
 * @param address the address to set
 */
public void setAddress(String address) {
    this.address = address;
}
/**
 * @return the gender
 */
public String getGender() {
    return gender;
}
/**
 * @param gender the gender to set
 */
public void setGender(String gender) {
    this.gender = gender;
}
/**
 * @return the contact_no
 */
public long getContact_no() {
    return contact_no;
}
/**
 * @param contact_no the contact_no to set
 */
public void setContact_no(long contact_no) {
    this.contact_no = contact_no;
}
/**
 * @return the contact_email
 */
public String getContact_email() {
    return contact_email;
}
/**
 * @param contact_email the contact_email to set
 */
public void setContact_email(String contact_email) {
    this.contact_email = contact_email;
}
/**
 * @return the resume
 */
public String getResume() {
    return resume;
}
/**
 * @param resume the resume to set
 */
public void setResume(String resume) {
    this.resume = resume;
}
/**
 * @return the dob
 */
public Date getDob() {
    return dob;
}
/**
 * @param dob the dob to set
 */
public void setDob(Date dob) {
    this.dob = dob;
}

/**
 * @return the loginDetailsModel
 */
@OneToOne(fetch = FetchType.LAZY)
@PrimaryKeyJoinColumn
public LoginDetailsModel getLoginDetailsModel() {
    return loginDetailsModel;
}

/**
 * @param loginDetailsModel the loginDetailsModel to set
 */
public void setLoginDetailsModel(LoginDetailsModel loginDetailsModel) {
    this.loginDetailsModel = loginDetailsModel;
}

以下是hibernate映射xml：

<beans:bean id="hibernate4AnnotatedSessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <beans:property name="dataSource" ref="dataSource" />
    <beans:property name="annotatedClasses">
        <beans:list>
            <beans:value>com.lic.agent.LoginDetailsModel</beans:value>
            <beans:value>com.lic.agent.LICUserInfoModel</beans:value>
        </beans:list>
    </beans:property>
    <beans:property name="hibernateProperties">
        <beans:props>
            <beans:prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect
            </beans:prop>
            <beans:prop key="hibernate.show_sql">true</beans:prop>
        </beans:props>
    </beans:property>
</beans:bean>

当我尝试使用hibernate技术在userinfo表中插入信息时，我得到以下异常：

org.hibernate.AnnotationException: Referenced property not a (One|Many)ToOne: com.lic.agent.LICUserInfoModel.loginDetailsModel in mappedBy of com.lic.agent.LoginDetailsModel.userInfoModel

非常感谢您解决此异常的任何帮助。谢谢你提前。

Answer 1

在您的类LICUserInfoModel中添加字段

的注释

@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "PK_ID")
private LoginDetailsModel loginDetailsModel;

指定用于关系的列

获取引用属性不是（一个|多个）ToOne Hibernate异常

1 个答案: