Question

我能够近似地比较Fluent Assertions中的两个2D矩形数组，如下所示：

float precision = 1e-5f;
float[,] expectedArray = new float[,] { { 3.1f, 4.5f}, { 2, 4} };
float[,] calculatedArray = new float[,] { { 3.09f, 4.49f}, { 2, 4} };

for (int y = 0; y < 2; ++y)
{
    for (int x = 0; x < 2; ++x)
    {
        calculatedArray[y,x].Should().BeApproximately(expectedArray[y,x], precision);
    }
}

但有没有更简洁的方法来实现这一点（没有for循环）？例如，与此相同的东西（用于一维数组）：

double[] source = { 10.01, 8.01, 6.01 };
double[] target = { 10.0, 8.0, 6.0  };

source.Should().Equal(target, (left, right) => Math.Abs(left-right) <= 0.01);

上述1D阵列的解决方案来自问题：Fluent Assertions: Compare two numeric collections approximately

Answer 1

目前框架中似乎没有支持此功能的任何内容。如果您不想在测试中使用循环，那么您可以选择一个选项来添加自己的扩展以涵盖此方案。

这有两个要素。第一种是添加一种扩展方法，将Should能力添加到2D数组中：

public static class FluentExtensionMethods
{
    public static Generic2DArrayAssertions<T> Should<T>(this T[,] actualValue)
    {
        return new Generic2DArrayAssertions<T>(actualValue);
    }
}

然后，您需要实现实际的断言类，它将包含比较循环：

public class Generic2DArrayAssertions<T> 
{
    T[,] _actual;

    public Generic2DArrayAssertions(T[,] actual)
    {
        _actual = actual;
    }

    public bool Equal(T[,] expected, Func<T,T, bool> func)
    {
        for (int i = 0; i < expected.Rank; i++)
            _actual.GetUpperBound(i).Should().Be(expected.GetUpperBound(i), 
                                                 "dimensions should match");

        for (int x = expected.GetLowerBound(0); x <= expected.GetUpperBound(0); x++)
        {
            for (int y = expected.GetLowerBound(1); y <= expected.GetUpperBound(1); y++)
            {
                func(_actual[x, y], expected[x, y])
                     .Should()
                     .BeTrue("'{2}' should equal '{3}' at element [{0},{1}]",
                      x, y, _actual[x,y], expected[x,y]);
            }
        }

        return true;
    }
}

然后，您可以在测试中使用它，就像其他断言一样：

calculatedArray.Should().Equal(expectedArray, 
                               (left,right)=> Math.Abs(left - right) <= 0.01);

我认为您的评论是在询问您如何测试我建议的扩展程序代码。答案是，和测试其他任何东西一样，传入值并验证输出。我在下面添加了一些测试（使用Nunit）来涵盖一些关键场景。有些事情需要注意，场景的数据是不完整的（似乎超出了范围，并且难以生成）。测试使用的是left == right的函数，因为要点是测试扩展，而不是对近似值的评估。

[TestCaseSource("differentSizedScenarios")]
public void ShouldThrowIfDifferentSizes(float[,] actual, float[,] expected)
{
    Assert.Throws<AssertionException>(()=>actual.Should().Equal(expected, (l, r) => l == r)).Message.Should().Be(string.Format("Expected value to be {0} because dimensions should match, but found {1}.", expected.GetUpperBound(0), actual.GetUpperBound(0)));
}

[TestCaseSource("missMatchedScenarios")]
public void ShouldThrowIfMismatched(int[,] actual, int[,] expected, int actualVal, int expectedVal, string index)
{
    Assert.Throws<AssertionException>(()=>actual.Should().Equal(expected, (l, r) => l.Equals(r))).Message.Should().Be(string.Format("Expected True because '{0}' should equal '{1}' at element [{2}], but found False.", actualVal, expectedVal, index));
}

[Test]
public void ShouldPassOnMatched()
{
    var expected = new float[,] { { 3.1f, 4.5f }, { 2, 4 } };
    var actual = new float[,] { { 3.1f, 4.5f }, { 2, 4 } };
    actual.Should().Equal(expected, (l, r) => l.Equals(r));
}

static object[] differentSizedScenarios = 
{
    new object[] {
        new float[,] { { 3.1f, 4.5f }, { 2, 4 } },
        new float[,] { { 3.1f, 4.5f }, { 2, 4 }, {1,2} }
    },
    new object[] {
        new float[,] { { 3.1f, 4.5f }, { 2, 4 } },
        new float[,] { { 3.1f, 4.5f }}
    }
    // etc...
};
static object[] missMatchedScenarios = 
{
    new object[] {
        new int[,] { { 1, 2}, { 3, 4 } },
        new int[,] { { 11, 2}, { 3, 4 } }
        ,1, 11, "0,0"
    },
    new object[] {
        new int[,] { { 1, 2}, { 3, 14 } },
        new int[,] { { 1, 2}, { 3, 4 } }
        ,14, 4, "1,1"
    },
    // etc...
};

Answer 2

我尚未对此进行全面测试，但以下方法似乎可行。

float precision = 0.1f; // Test passes with this level of precision.
//float precision = 0.01f; // Test fails with this level of precision.
float[,] expectedArray = new float[,] { { 3.1f, 4.5f }, { 2, 4 } };
float[,] calculatedArray = new float[,] { { 3.09f, 4.49f }, { 2, 4 } };

calculatedArray.Should().BeEquivalentTo(
    expectedArray,
    options => options
        .ComparingByValue<float>()
        .Using<float>(ctx => ctx.Subject.Should().BeApproximately(ctx.Expectation, precision))
        .WhenTypeIs<float>());

流畅断言：近似比较两个2D矩形阵列

2 个答案: