Question

我有一个图像视图

这

过了这个

我希望根据媒体播放器音乐进行缩放（如果可以用于低音）它的目的是让它看起来像一个扬声器。我发现了这个，可能是ultil

public class Visulizer extends Activity {

TextView mStatusView;
MediaRecorder mRecorder;
Thread runner;
private static double mEMA = 0.0;
static final private double EMA_FILTER = 0.6;

final Runnable updater = new Runnable(){

    public void run(){
        updateTv();
    };
};
final Handler mHandler = new Handler();

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.noiselevel);
    mStatusView = (TextView) findViewById(R.id.status);


    if (runner == null)
    {
        runner = new Thread(){
            public void run()
            {
                while (runner != null)
                {
                    try
                    {
                        Thread.sleep(1000);
                        Log.i("Noise", "Tock");
                    } catch (InterruptedException e) { };
                    mHandler.post(updater);
                }
            }
        };
        runner.start();
        Log.d("Noise", "start runner()");
    }
}

public void onResume()
{
    super.onResume();
    startRecorder();
}

public void onPause()
{
    super.onPause();
    stopRecorder();
}

public void startRecorder(){
    if (mRecorder == null)
    {
        mRecorder = new MediaRecorder();
        mRecorder.setAudioSource(MediaRecorder.AudioSource.MIC);
        mRecorder.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP);
        mRecorder.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB);
        mRecorder.setOutputFile("/dev/null");
        try
        {
            mRecorder.prepare();
        }catch (java.io.IOException ioe) {
            android.util.Log.e("[Monkey]", "IOException: " +
                    android.util.Log.getStackTraceString(ioe));

        }catch (java.lang.SecurityException e) {
            android.util.Log.e("[Monkey]", "SecurityException: " +
                    android.util.Log.getStackTraceString(e));
        }
        try
        {
            mRecorder.start();
        }catch (java.lang.SecurityException e) {
            android.util.Log.e("[Monkey]", "SecurityException: " +
                    android.util.Log.getStackTraceString(e));
        }

        //mEMA = 0.0;
    }

}
public void stopRecorder() {
    if (mRecorder != null) {
        mRecorder.stop();
        mRecorder.release();
        mRecorder = null;
    }
}

public void updateTv(){
    mStatusView.setText(Double.toString((getAmplitudeEMA())) + " dB");
}
public double soundDb(double ampl){
    return  20 * Math.log10(getAmplitudeEMA() / ampl);
}
public double getAmplitude() {
    if (mRecorder != null)
        return  (mRecorder.getMaxAmplitude());
    else
        return 0;

}
public double getAmplitudeEMA() {
    double amp =  getAmplitude();
    mEMA = EMA_FILTER * amp + (1.0 - EMA_FILTER) * mEMA;
    return mEMA;
}

}

但我在这里很困惑。我想保持这个简单......我认为FFT和听起来很复杂......

Answer 1

这是真正的音频处理具有挑战性。但您可以使用第三方库，它提供了一些可以用于您的案例的方法。

在您的情况下，您需要检测声压级并相应地更新您的图纸。

这是一些用于检测声压级的库。

根据音乐移动视图

1 个答案: