Question

我正在编写一个从数据库中获取数据并显示它的脚本。我需要它仅显示每页上某个日期的数据，即html输入表单定义的日期。看看代码。

     }else{
        //date selector - this chooses which date to display the data. The output of this needs to
    be what date the data is sorted by.
        $date = date('Y-m-d');
        echo "
        <input type='date' name='date' value='$date'>";
        //include the database connection so you can fetch data from the table 'notices'
        include("db.php");
        //sql fetching data from the database ad displaying it
//Each row of data is currently sorted by the field id, which is currently auto-incrementing
        $sql = "SELECT * FROM notices ORDER BY id DESC";
        $stmt = $db->query($sql);
        $stmt->execute();
        $stmt->setFetchMode(PDO::FETCH_ASSOC);
            if($stmt->rowCount() > 0){
                while($row = $stmt->fetch()){
                echo "
                <p><b>".$row['subject']."</b></p>
                <p>".$row['message']."</p>
                <p>".$row['name']."<br></p>
                <hr>
                ";
                }
            }
        }

任何帮助都将非常感激。感谢。

Answer 1

你可以使用mysqli查询从数据库中显示一个像这样的简单代码

if ($result = mysqli_query($link, "SELECT date FROM database where date = your html form input date")) {
    printf("Select returned %d rows.\n", mysqli_num_rows($result));

    /* free result set */
    mysqli_free_result($result);
}

从某个日期获取mysqli的表格数据

1 个答案: