我在理解如何嵌套3个模型时遇到了一些问题。我试图在关系的最深处向Video
添加WorkoutSteps
(不创建新视频,但从下拉列表中选择现有视频)
型号:
Workout
WorkoutSet
WorkoutStep
- >只是一个Video
的数组
Video
关系
锻炼:
has_and_belongs_to_many :workout_sets, :join_table => :workout_sessions, dependent: :destroy
WorkoutSet
has_and_belongs_to_many :workout_steps, :join_table => :sets_steps, dependent: :destroy
WorkoutStep
has_and_belongs_to_many :workout_sets, :join_table => :sets_steps
以下是观点:
_form.html.haml
= simple_form_for(@workout, url: admin_workouts_path(@workout)) do |f|
= f.input :title
%h3 Sets
.sets.some{ :style => "margin-left: 25px" }
= f.simple_fields_for :workout_sets do |set|
= render 'workout_set_fields', f: set
.links
= link_to_add_association 'add set', f, :workout_sets
= f.submit
_workout_set_fields
= f.label :title
= f.text_field :title
%br
%br
#sets.some{ :style => "margin-left: 25px" }
= f.simple_fields_for :workout_steps do |step|
= render 'workout_step_fields', f: step
.links
= link_to_add_association 'add step', f, :workout_steps
_workout_step_fields
= f.association :main_videos, include_hidden: false
workouts_controller.rb
def workout_params
params.require(:workout).permit(:title, :pro, :workout_step_id, workout_sets_attributes: [ :id, :_destroy, :title, workout_steps_attributes: [ main_video_ids: [:id] ] ])
end
检查参数:
答案 0 :(得分:0)
main_video_ids
是一个数组属性,而不是id
的散列。所以你可以直接将它列入白名单:
def workout_params
params.require(:workout).permit(:title, :pro, :workout_step_id, workout_sets_attributes: [ :id, :_destroy, :title, workout_steps_attributes: main_video_ids: [] ] ])
end