我一直试图窥探在控制器初始化时执行的功能,但测试总是失败。
我一直在尝试执行$scope.$digest()
并且它无法正常工作,但是在控制台中,我看到该函数已被调用。
我无法弄清楚这一点,有人可以向我解释为什么它不起作用?
Codepen示例: http://codepen.io/gpincheiraa/pen/KzZNby
控制器
function Controller($stateParams, $scope){
$scope.requestAuthorization = requestAuthorization;
if ($stateParams.requestAuthorization === true) {
console.log('$stateParams.requestAuthorization');
$scope.requestAuthorization();
}
function requestAuthorization() {
console.log('requestAuthorization()');
}
}
测试
describe('AppCtrl', function(){
var AppCtrl, $rootScope, $scope, $stateParams;
beforeEach(module('exampleApp'));
beforeEach(inject(function($controller, _$rootScope_, _$injector_, _$stateParams_) {
$rootScope = _$rootScope_;
$scope = $rootScope.$new();
$stateParams = _$stateParams_;
$stateParams.requestAuthorization = true;
AppCtrl = $controller('AppCtrl',{
$scope: $scope,
$stateParams : $stateParams
});
spyOn($scope, 'requestAuthorization');
}));
it('$stateParams.requestAuthorization should be defined', function() {
expect($stateParams.requestAuthorization).toBeDefined();
});
it('$scope.requestAuthorization should be defined', function() {
expect($scope.requestAuthorization).toBeDefined();
});
// this test is not passing..
it('should call requestAuthorization', function() {
//$scope.$digest();
expect($scope.requestAuthorization).toHaveBeenCalled();
});
});
答案 0 :(得分:7)
您的测试失败,因为当控制器初始化时,间谍会被真实函数覆盖。避免这种情况的一种方法是使用$scope
属性的自定义setter来修补requestAuthorization
对象,当控制器尝试为此属性赋值时,可能会创建间谍:
beforeEach(inject(function($controller, _$rootScope_, _$injector_, _$stateParams_) {
$rootScope = _$rootScope_;
$scope = $rootScope.$new();
var reqAuthSpy;
Object.defineProperty($scope, 'requestAuthorization', {
get: function() {return reqAuthSpy;},
set: function(fn) {
reqAuthSpy = jasmine.createSpy('reqAuthSpy');
}
});
$stateParams = _$stateParams_;
$stateParams.requestAuthorization = true;
AppCtrl = $controller('AppCtrl',{
$scope: $scope,
$stateParams : $stateParams
});
}));