找到两个相同圆圈的百分比叠加级别

Question

我必须有两个圆圈（圆圈-1，圆圈-2），其中心为x1，y1和x2，y2随后具有相同的尺寸。

现在我要计算cir1在cir1上的叠加百分比（百分比） （ex）如果cir2完全覆盖cir1然后叠加= 100％ 如果完成一半叠加，则得分将为50％，如果不叠加则= 0％。

怎么做.....？

任何指南......

Answer 1

Thanks Andy. 
I got an idea from the link you provide. 
Though the idea is not the best, but it solves the purpose..

double radius = 40.0;
int x1 =100;    //first Circle X value
int y1 = 100;   //first Circle Y value
int x2 = 100;   //second Circle X value
int y2 = 100;  //second Circle Y value

double iDist = Math.sqrt((x2-x1)*(x2-x1) + (y2-y1)*(y2-y1));
double per = (100.0-(iDist/radius)*100);    //get the value in %
System.out.println("Distance: "+iDist + "("+per+"%)");


OUTPUT:

if values are (100,100) and (100,100) then o/p : 100%
if values are (100,100) and (120,100) then o/p : 50%
if values are (100,100) and (140,100) then o/p : 0%
if values are (100,100) and (600,600) then o/p : percentage in negative value (ex) - 973%


All the best....!