我是Lodash和功能编程概念的新手。所以,我有一系列具有日期日期的对象:
[
{
"date": '1-Jan-2015',
"count": 4
},
{
"date": '4-Jan-2015',
"count": 3
},
{
"date": '1-Feb-2015',
"count": 4
},
{
"date": '18-Feb-2015',
"count": 10
}
]
我希望减少和聚合它,以便获得一个对象数组,其中每个对象都有月度数据,而不是像这样的日常数据:
[
{
"date": 'Jan, 2015',
"count": 7 // aggregating the count of January
},
{
"date": 'Feb, 2015',
"count": 14 //aggregating the count of February
}
]
目前,我写了一个非常难以理解和复杂的代码,其中包含ifs和fors。但是,我想用lodash重构它。是否有可能使用lodash?我环顾四周,找到了_.reduce
和_.groupBy
,我可以使用它,但我现在很难过,无法找到一个干净的实施方案。
答案 0 :(得分:3)
你不需要lodash
来实现你想要的,你可以使用普通的旧Javascript:
var array = [{
"date": '1-Jan-2015',
"count": 4
}, {
"date": '4-Jan-2015',
"count": 3
}, {
"date": '1-Feb-2015',
"count": 4
}, {
"date": '18-Feb-2015',
"count": 10
}]
var result = array.reduce(function(ar, item) {
var index = item.date.split('-').slice(1,3).join(', ') //getting date Month-Year
_item = ar.filter(function(a) {
return a.date === index
})[0] // getting item if already present in array
// getting index of _item if _item is already present in ar
indexOf = ar.indexOf(_item)
if(indexOf > -1)
// we sum the count of existing _item
ar[indexOf] = {date: index, count: count: _item.count + item.count }
else
// item is not yet in the array, we push a new _item
ar.push({date: index, count: item.count})
return ar; // return the array as required by reduce
}, []) // initialize the reduce method with an empty array
console.log(result) // your array with aggregated dates
有趣的是,lodash
版本:
_.values(array.reduce(function(obj, item) {
var index = item.date.split('-').slice(1, 3).join(', ')
obj[index] = {date: index, count: (obj[index] && obj[index].count || 0) + item.count}
return obj
}, {}))
答案 1 :(得分:3)
我们可以使用_.reduce
& _.values
var arr = [
{
"date": '1-Jan-2015',
"count": 4
},
{
"date": '4-Jan-2015',
"count": 3
},
{
"date": '1-Feb-2015',
"count": 4
},
{
"date": '18-Feb-2015',
"count": 10
}
]
_.values(_.reduce(arr,function(result,obj){
var name = obj.date.split('-');
name = name[1]+', '+name[2];
result[name] = {
date:name,
count:obj.count + (result[name]?result[name].count:0)
};
return result;
},{}));