预处理器为m68k定义和宏?

时间:2016-04-06 05:42:05

标签: macros c-preprocessor

对于m68k,我们在Debian's testing/build infrastructure下的构建失败:

<context:component-scan>

修复很简单,但我需要知道预处理器为平台定义的内容。我没有具有该体系结构的计算机,因此我无法使用config.h:29:3: error: #error "IS_LITTLE_ENDIAN is set, but __BYTE_ORDER__ does not equal __ORDER_LITTLE_ENDIAN__" # error "IS_LITTLE_ENDIAN is set, but __BYTE_ORDER__ does not equal __ORDER_LITTLE_ENDIAN__" 转储它们。

有人可以提供m68k的预处理器输出吗?

1 个答案:

答案 0 :(得分:0)

如果您愿意消磨时间,可以为该平台构建交叉编译器。如果您关心该特定标志,请尝试将此测试添加到configure.ac

#include <stdint.h>

enum {
  ENDIAN_UNKNOWN,
  ENDIAN_BIG,
  ENDIAN_LITTLE,
  ENDIAN_BIG_WORD,   /* Middle-endian, Honeywell 316 style */
  ENDIAN_LITTLE_WORD /* Middle-endian, PDP-11 style */
};

int endianness(void)
{
  union
  {
    uint32_t value;
    uint8_t data[sizeof(uint32_t)];
  } number;

  number.data[0] = 0x00;
  number.data[1] = 0x01;
  number.data[2] = 0x02;
  number.data[3] = 0x03;

  switch (number.value)
  {
  case UINT32_C(0x00010203): return ENDIAN_BIG;
  case UINT32_C(0x03020100): return ENDIAN_LITTLE;
  case UINT32_C(0x02030001): return ENDIAN_BIG_WORD;
  case UINT32_C(0x01000302): return ENDIAN_LITTLE_WORD;
  default:                   return ENDIAN_UNKNOWN;
  }
}