Question

需要了解_findfirst和_findnext如何使用模式输入。

我曾经按照代码来分析他们的功能，但结果让我感到困惑。

    intptr_t handle;
    struct _finddata_t fblock;
    int count = 1;
    char pattern[] = "*";
    printf("Pattern is %s",pattern);
    if((handle = _findfirst(pattern,&fblock))>0){
        printf("\nfound : %d :: ",count++);
        printf("%s",fblock.name);
        while(_findnext(handle,&fblock) == 0){
            printf("\nfound : %d :: ",count++);
            printf("%s",fblock.name);
        }
    }
    printf("\ncompleted");
    //getch();

结果：我在文件夹中有四个文件。

1.ReadMe.txt
2.ReadMe1.txt
3.ReadMe1.txt_bck
4.ReadMe1.txtbck

现在，

Enter pattern :*.tx
Pattern is *.tx
completed

确定。没有带有ext tx的文件

Enter pattern :*.txt_
Pattern is *.txt_
completed

确定。没有带有ext txt_的文件

Enter pattern :*.txt
Pattern is *.txt
found : 1 :: ReadMe.txt
found : 2 :: ReadMe1.txt
found : 3 :: ReadMe1.txtbck
found : 4 :: ReadMe1.txt_bck
completed

???我只询问了ext txt。为什么要显示txt_bck？

Enter pattern :*.txt*
Pattern is *.txt*
found : 1 :: ReadMe.txt
found : 2 :: ReadMe1.txt
found : 3 :: ReadMe1.txtbck
found : 4 :: ReadMe1.txt_bck
completed

现在这与prev之间的差异是什么？

Enter pattern :ReadMe?.txt
Pattern is ReadMe?.txt
found : 1 :: ReadMe.txt
found : 2 :: ReadMe1.txt
completed

期待“？”通配符只匹配一个字符但它也匹配0。

Enter pattern :ReadMe*.txt
Pattern is ReadMe*.txt
found : 1 :: ReadMe.txt
found : 2 :: ReadMe1.txt
found : 3 :: ReadMe1.txtbck
found : 4 :: ReadMe1.txt_bck
completed

_

了解_findfirst和_findnext

0 个答案: