Question

我对Android很陌生，我正在尝试重新创建一个旧的iPhone游戏（Llama或Duck），你可以在其中看到一张图片，然后选择图片所描绘的动物。该代码适用于一些图片，然后在onCreate方法中出现OutOfMemory错误，无论屏幕上的图片是什么。我已经查看了其他问题并看到有一个Bitmap方法（回收）可以解决问题，但我不知道如何实现它或它是否与我的问题相关。任何和所有的帮助表示赞赏。

package com.example.ryan.llamaorduck;

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;

import java.util.Random;

public class DuckScreen extends AppCompatActivity {

boolean isLlamaScreen = false; //false because this is the Duck screen
Intent intent;
int screen; // variable used just for finding the next random screen

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_duck_screen);
}

// user clicked on the llama button.
//method implementation decides if they are correct and either ends the 
//game or moves them onto the next random page.       
public void llamaClick(View view){
    if (isLlamaScreen){
        Random r = new Random();
        screen = r.nextInt(2);
        if (screen == 1){ //DUCK
            intent = new Intent(DuckScreen.this,DuckScreen.class);
            startActivity(intent);
        } else{
            intent = new Intent(DuckScreen.this,LlamaScreen.class);
            startActivity(intent);
        }
    }else{
        intent = new Intent(DuckScreen.this,GameOver.class);
        startActivity(intent);
    }
}
//user clicked on the button indicating that they think the animal is a
//duck. Same idea as method before, testing other button.         
public void duckClick(View view){
    if (!isLlamaScreen){
        Random r = new Random();
        screen = r.nextInt(2);
        if (screen == 1){ //DUCK
            intent = new Intent(DuckScreen.this,DuckScreen.class);
            startActivity(intent);
        } else{
            intent = new Intent(DuckScreen.this,LlamaScreen.class);
            startActivity(intent);
        }
    }else{
        intent = new Intent(DuckScreen.this,GameOver.class);
        startActivity(intent);
    }
}
}

XML：

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"

tools:context="com.example.ryan.llamaorduck.DuckScreen">

<ImageView
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:layout_weight="2"
    android:src="@drawable/duck"
    android:scaleType="centerCrop"
    android:id="@+id/duck"
    />

<RadioGroup
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignBottom="@id/duck"
    android:orientation="vertical"
    >
    <RadioButton
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="Duck"
        android:textSize="30sp"
        android:onClick="duckClick"
        />
    <RadioButton
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="Llama"
        android:textSize="30sp"
        android:onClick="llamaClick"
        />
</RadioGroup>

</RelativeLayout>

Answer 1

如果您不需要保留活动历史记录，一种解决方案是在开始新活动时使用FLAG_ACTIVITY_CLEAR_TOP标记。所以你的代码就像：

package com.example.ryan.llamaorduck;

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;

import java.util.Random;

public class DuckScreen extends AppCompatActivity {

boolean isLlamaScreen = false; //false because this is the Duck screen
Intent intent;
int screen; // variable used just for finding the next random screen

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_duck_screen);
}

// user clicked on the llama button.
//method implementation decides if they are correct and either ends the 
//game or moves them onto the next random page.       
public void llamaClick(View view){
    if (isLlamaScreen){
        Random r = new Random();
        screen = r.nextInt(2);
        if (screen == 1){ //DUCK
            intent = new Intent(DuckScreen.this,DuckScreen.class);
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
        } else{
            intent = new Intent(DuckScreen.this,LlamaScreen.class);
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
        }
    }else{
        intent = new Intent(DuckScreen.this,GameOver.class);
        intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        startActivity(intent);
    }
}
//user clicked on the button indicating that they think the animal is a
//duck. Same idea as method before, testing other button.         
public void duckClick(View view){
    if (!isLlamaScreen){
        Random r = new Random();
        screen = r.nextInt(2);
        if (screen == 1){ //DUCK
            intent = new Intent(DuckScreen.this,DuckScreen.class);
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
        } else{
            intent = new Intent(DuckScreen.this,LlamaScreen.class);
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(intent);
        }
    }else{
        intent = new Intent(DuckScreen.this,GameOver.class);
        intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        startActivity(intent);
    }
}
}

Android游戏（Llama或Duck）OutOfMemory错误

1 个答案: