对我来说,这似乎只是最简单的Spring集成示例。我正在尝试向si4demo学习。但是当我运行它时,我得到了这个例外:
线程“main”中的异常 org.springframework.messaging.MessageDeliveryException:Dispatcher有 没有订阅者'channel.inbox'。嵌套异常是 org.springframework.integration.MessageDispatchingException: Dispatcher没有订阅者
我哪里错了?定义的流是否创建了对收件箱渠道的订阅?
import org.springframework.boot.SpringApplication;
import org.springframework.context.ConfigurableApplicationContext;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.integration.annotation.IntegrationComponentScan;
import org.springframework.integration.annotation.MessagingGateway;
import org.springframework.integration.channel.DirectChannel;
import org.springframework.integration.dsl.IntegrationFlow;
import org.springframework.integration.dsl.IntegrationFlows;
import org.springframework.messaging.MessageChannel;
@Configuration
@ComponentScan
@IntegrationComponentScan
public class App {
public static void main(String[] args) {
try (ConfigurableApplicationContext ctx = SpringApplication.run(App.class, args)) {
final Gateway gateway = ctx.getBean(Gateway.class);
final String rs = gateway.send("hullo");
System.out.println(rs);
}
}
private static final String INBOX = "inbox";
@MessagingGateway(defaultRequestChannel = INBOX)
public interface Gateway {
String send(String msg);
}
@Bean
public IntegrationFlow flow() {
return IntegrationFlows.from(INBOX)
.transform(p -> "world")
.get();
}
@Bean(name = INBOX)
public MessageChannel inbox() {
return new DirectChannel();
}
}
答案 0 :(得分:3)
看起来你错过了主要播放器 - <RelativeLayout>
...
<fragment
android:name= "packagename.button_fragment"
...width, height, id, postion... />
<fragment
android:name= "packagename.bMenu"
...width, height, id, postion... />
:
从版本4.0开始,引入了
@EnableIntegraion
注释,以允许注册Spring Integration基础结构bean(请参阅JavaDocs)。只有Java和Java时才需要这个注释。使用注释配置,例如, Spring Boot和/或Spring Integration Messaging Annotation支持和Spring Integration Java DSL,没有XML集成配置。