我在第21行收到ERROR 1064(42000),这是Vehicle表中的VIN_Number。实体库存构建没有问题,VIN_Number的类型为varchar(17),适用于所有实例。我相信这些表是按照正确的顺序构建的。我找不到任何拼写或标点符号错误。我不相信我应该检查的事情。我错过了什么?
注意:我也收到了Invoice的错误,但我知道在创建Vehicle之前无法创建它。
ALTER TABLE Vehicle DROP FOREIGN KEY fk_Veh_Vehicle_TypeID;
ALTER TABLE Inventory DROP FOREIGN KEY fk_Inv_Vehicle_TypeID;
ALTER TABLE Invoice DROP FOREIGN KEY fk_Customer_ID;
ALTER TABLE Invoice DROP FOREIGN KEY fk_Sales_Person_ID;
ALTER TABLE Invoice DROP FOREIGN KEY fk_VIN_Number;
DROP TABLE IF EXISTS Vehicle, VehicleType,
Invoice, Customer, SalesPerson, Inventory;
CREATE TABLE VehicleType (
Vehicle_TypeID int NOT NULL,
Veh_Make varchar(15),
Veh_Model varchar(15),
Veh_Year int,
PRIMARY KEY (Vehicle_TypeID)
) Engine=InnoDB;
CREATE TABLE Vehicle (
VIN_Number varchar(17) NOT NULL,
Vehicle_TypeID int NOT NULL,
Condition varchar(10),
Color varchar(8),
PRIMARY KEY (VIN_Number),
CONSTRAINT fk_Veh_Vehicle_TypeID FOREIGN KEY(Vehicle_TypeID)
REFERENCES VehicleType(Vehicle_TypeID)
) Engine=InnoDB;
CREATE TABLE Inventory (
Stock_ID int NOT NULL,
Vehicle_TypeID int NOT NULL,
Quantity int,
PRIMARY KEY (Stock_ID),
CONSTRAINT fk_Inv_Vehicle_TypeID FOREIGN KEY (Vehicle_TypeID)
REFERENCES VehicleType(Vehicle_TypeID)
) Engine=InnoDB;
CREATE TABLE Customer (
Customer_ID varchar(10) NOT NULL,
Cus_LastName varchar(15),
Cus_FirstName varchar(15),
Cus_Street varchar(20),
Cus_City varchar(15),
Cus_Zip varchar(5),
Cus_Phone varchar(10),
PRIMARY KEY (Customer_ID)
) Engine=InnoDB;
CREATE TABLE SalesPerson (
Sales_Person_ID varchar(10) NOT NULL,
Sal_LastName varchar(15),
Sal_FirstName varchar(15),
Sal_Street varchar(15),
Sal_City varchar(15),
Sal_Zip varchar(5),
Sal_Phone varchar(10),
Sal_Years_Worked int,
Sal_Commission_Rate float(4),
PRIMARY KEY (Sales_Person_ID)
) Engine=InnoDB;
CREATE TABLE Invoice (
Invoice_ID varchar(10) NOT NULL,
Customer_ID varchar(10) NOT NULL,
Sales_Person_ID varchar(10) NOT NULL,
VIN_Number varchar(17) NOT NULL,
Price float(10),
PRIMARY KEY (Invoice_ID),
CONSTRAINT fk_Customer_ID FOREIGN KEY (Customer_ID)
REFERENCES Customer(Customer_ID),
CONSTRAINT fk_Sales_Person_ID FOREIGN KEY (Sales_Person_ID)
REFERENCES SalesPerson(Sales_Person_ID),
CONSTRAINT fk_VIN_Number FOREIGN KEY (VIN_Number)
REFERENCES Vehicle(VIN_Number)
) Engine=InnoDB;
答案 0 :(得分:1)
在Vehicle表的定义中,您有一个名为condition
的列,它是MySQL中的保留关键字(reference)。要么为列使用其他名称,要么将其括在反引号中,如下所示:`condition`
对象名称使用关键字(保留与否)通常是您要避免的。