所以我将字符串值发送到数据库
@string = 'Value1|Value2|Value3|Value4, OtherVal1|OtherVal2|OtherVal3|OtherVal4'
还有其他一些内容
@id ='1'
我想首先将它拆分为',然后将其拆分为|并插入表格
实施例
TABLE
ID | COLUMN1 |COLUMN2 |COLUMN3 |COLUMN4 |COLUMN5
ai | @id | value1 |value2 |value3 |value4
ai | @id2 |otherVal1 |otherVal2 |otherVal3 |otherVal4
这是我到目前为止所做的代码,但是我的另一个函数返回值按值,
DECLARE @string nvarchar(max)
DECLARE @IDSet nvarchar(max)
DECLARE @columnsValue nvarchar(max)
DECLARE @columnsPos int
DECLARE @pos int
DECLARE @nextPost int
DECLARE @delimiter nchar(1)
DECLARE @delimiter2 nchar(1)
SET @delimiter2 = '|'
SET @delimiter = ','
SET @string = 'ColumnName|autocompleteId|autocompleteValue|AndOrStatus,ColumnName1|autocompleteId1|autocompleteValue1|AndOrStatus1' + @delimiter
SET @pos = charindex(@delimiter, @string)
WHILE(@pos <> 0)
BEGIN
SET @IDSet = substring(@string,1,@pos -1) + @delimiter2
--SELECT @IDSet
SET @columnsPos = charindex(@delimiter2,@IDSet)
WHILE(@columnsPos <> 0)
BEGIN
SET @columnsValue = substring(@IDSet ,1,@columnsPos - 1)
SELECT @columnsValue
SET @IDSet = substring(@IDSet,@columnsPos +1, LEN(@IDSet))
SET @columnsPos = charindex(@delimiter2,@IDSet)
END
SET @string = substring(@string,@pos + 1,LEN(@string))
SET @pos = charindex(@delimiter,@string)
END
当前代码经过两个while语句并按其分隔符
分割代码任何想法如何从中插入表格。
答案 0 :(得分:0)
以下是使用PARSENAME
首先使用任何拆分字符串方法拆分值。我用XML
方法拆分了字符串
然后使用PARSENAME
函数将值拆分为列
DECLARE @string VARCHAR(500)=
'Value1|Value2|Value3|Value4, OtherVal1|OtherVal2|OtherVal3|OtherVal4';
WITH cte
AS (SELECT Replace(Rtrim(Ltrim(split.a.value('.', 'VARCHAR(100)'))), '|','.') AS split_data
FROM (SELECT Cast ('<M>' + Replace(@string, ',', '</M><M>')
+ '</M>' AS XML) AS Data) AS A
CROSS apply data.nodes ('/M') AS Split(a))
SELECT COLUMN2= Parsename(split_data, 4),
COLUMN3=Parsename(split_data, 3),
COLUMN4= Parsename(split_data, 2),
COLUMN5=Parsename(split_data, 1)
FROM cte
在 SQL Server 2016 中,您可以使用STRING_SPLIT
函数拆分数据
;WITH cte
AS (SELECT split_data = Replace(Rtrim(Ltrim(value)), '|', '.')
FROM String_split(@string, ','))
SELECT COLUMN2= Parsename(split_data, 4),
COLUMN3=Parsename(split_data, 3),
COLUMN4= Parsename(split_data, 2),
COLUMN5=Parsename(split_data, 1)
FROM cte
结果:
╔═══════════╦═══════════╦═══════════╦═══════════╗
║ COLUMN2 ║ COLUMN3 ║ COLUMN4 ║ COLUMN5 ║
╠═══════════╬═══════════╬═══════════╬═══════════╣
║ Value1 ║ Value2 ║ Value3 ║ Value4 ║
║ OtherVal1 ║ OtherVal2 ║ OtherVal3 ║ OtherVal4 ║
╚═══════════╩═══════════╩═══════════╩═══════════╝