这里只是一个简单的java问题...我想拆分一个字符串并获取一个特定的部分将其转换为双精度:
#include <string>
#include <sstream>
#include <iostream>
#include <fstream>
#include <iomanip>
#include <cstdlib>
using namespace std;
struct intNode {
int data;
intNode * Left;
intNode * Right;
int height;
intNode(int input, intNode * iLeft= NULL, intNode * iRight = NULL) {
data = input;
Left = iLeft;
Right = iRight;
height = 0;
}
};
int getHeight(intNode* temp) {
if (temp == NULL)
return 0;
return temp->height;
}
void setHeight(intNode * temp)
{
int hLeft = getHeight(temp->Left);
int hRight = getHeight(temp->Right);
temp->height = 1 + max(hLeft, hRight);
}
int getBalance(intNode * temp) {
if (temp == NULL) {
return 0;
} else {
return getHeight(temp->Left) - getHeight(temp->Right);
}
}
struct intTree {
intNode * root;
intTree();
void addNode(int input);
void addNode(int input, intNode *& root);
void print();
void print(intNode *input);
intNode * balanceTree(intNode *& sub);
intNode * rotateRight(intNode *& sub);
intNode * rotateLeft(intNode *& sub);
};
void intTree::print(intNode *input) {
if (input != NULL) {
print(input->Left);
cout << input->data << endl;
print(input->Right);
}
}
void intTree::print() {
print(root);
}
intNode * intTree::rotateRight(intNode *& subTree) {
intNode * newRoot = subTree->Left;
subTree->Left = newRoot->Right;
newRoot->Right = subTree;
setHeight(subTree);
setHeight(newRoot);
return newRoot;
}
intNode * intTree::rotateLeft(intNode *& subTree) {
intNode * newRoot = subTree->Right;
subTree->Right = newRoot->Left;
newRoot->Left = subTree;
setHeight(subTree);
setHeight(newRoot);
return newRoot;
}
intNode* intTree::balanceTree(intNode *& subTree) {
setHeight(subTree);
if (getBalance(subTree) == 2 && getBalance(subTree->Right) < 0) {
cout << "RL" << endl;
subTree->Left = rotateLeft(subTree->Left);
return rotateRight(subTree);
} else if (getBalance(subTree) == 2) { // RR
cout << "RR" << endl;
return rotateRight(subTree);
} else if (getBalance(subTree) == -2 && getBalance(subTree->Left) > 0) { // LR
cout << "LR" << endl;
subTree->Right = rotateRight(subTree->Right);
return rotateLeft(subTree);
} else if (getBalance(subTree) == -2) { // LL
cout << "LL" << endl;
return rotateLeft(subTree);
} else {
return subTree; // balanced
}
}
intTree::intTree() {
root = NULL;
}
void intTree::addNode(int input, intNode *& temp) {
if (temp == NULL) {
temp = new intNode(input);
} else if (input < temp->data) {
cout <<" added to the left" << endl;
addNode(input,temp->Left);
} else if (input > temp->data) {
cout <<" added to the right" << endl;
addNode(input, temp->Right);
}
temp = balanceTree(temp);
}
void intTree::addNode(int input) {
addNode(input, root);
}
void read() {
string num;
int balance, input;
int i = 0;
intTree * intBST = new intTree();
while (i != 10) {
cout << "number?" << endl;
cin >> input;
intNode *tempInt= new intNode(input);
intBST->addNode(input);
i++;
}
cout << "Finished reading in files" << endl;
while (true) {
string userInput;
cin >> userInput;
if (userInput == "Exit") {
cout << "Goodbye!" << endl;
return;
}
if (userInput == "Print") {
intBST->print();
return;
}
}
}
void main() {
read();
return 0;
}
最简单的方法是将13.50作为双倍。 我想把它们分成两个,首先是单词,然后是美元价值。使用.split(&#34; - &#34;);
谢谢大家。
答案 0 :(得分:1)
Double.valueOf(name.split("\\$")[1])
答案 1 :(得分:1)
您可以使用正则表达式,编译Pattern
并使用Matcher
。像,
String name = "England vs Spain -- $13.50";
Pattern p = Pattern.compile("(.+)\\s*--\\s*\\$(.+)");
Matcher m = p.matcher(name);
if (m.matches()) {
System.out.println("Words: " + m.group(1));
System.out.printf("Amount: $%.2f%n", Double.parseDouble(m.group(2)));
}
输出
Words: England vs Spain
Amount: $13.50