Question

我每个月都有一张销售记录表。在这种情况下，每个推销员都有自己的代码bd和nk。

的MySQL

select sale_plc
      , month(sale_date) as mon
      , sum(sale_cost) as cost 
from daily_sales 
 where year(sale_date)='2016' 
group 
    by year(sale_date)
      , month(sale_date)
      , sale_plc 
order 
    by month(sale_date)
      , sale_plc asc 
 LIMIT 0, 30

在查询之后我得到了这个结果：

id  mon cost
bd  1   224787
nk  1   721102
bd  2   440399
nk  2   898020
bd  3   363543
nk  3   878250

虽然

id =销售员代码（sale_plc）
mon =月号
费用 =此ID的本月总销售额。

根据结果。我希望结果像这样的数组。阵列

(
    [1] => Array
        (
            [mon] => 1
            [bd] => 224787
            [nk] => 721102
        )
    [2] => Array
        (
            [mon] => 2
            [bd] => 440399
            [nk] => 898020
        )
    [3] => Array
        (
            [mon] => 3
            [bd] => 363543
            [nk] => 878250
        )
    )

我知道这与sale_plc有关。我需要制作阵列，但我不知道这样做。

Answer 1

我没有你的SQL输出，所以我创建一个数组并使用与我对你的数组相同的功能创建我自己的代码。

<强> PHP

$arr = array(array("id" => "bd", "mon" => "1", "cost" => "224787"),
            array("id" => "nk", "mon" => "1", "cost" => "721102"),
            array("id" => "bd", "mon" => "2", "cost" => "440399"),
            array("id" => "nk", "mon" => "2", "cost" => "898020"),
            array("id" => "bd", "mon" => "3", "cost" => "363543"),
            array("id" => "nk", "mon" => "3", "cost" => "878250"),
            );

$output_arr = array();      
$tmp = 0;
foreach($arr as $key => $value){
    if($tmp == 0 || $tmp != $value['mon'])
        $output_arr[$value['mon']][mon] = $value['mon'];
    if($value['id'] == 'bd')
        $output_arr[$value['mon']][$value['id']] = $value['cost'];
    if($value['id'] == 'nk')
        $output_arr[$value['mon']][$value['id']] = $value['cost'];
    $tmp = $value['mon'];
}
echo "<pre>";
print_r($output_arr);
echo "</pre>";

<强>输出

Array
(
    [1] => Array
        (
            [mon] => 1
            [bd] => 224787
            [nk] => 721102
        )

    [2] => Array
        (
            [mon] => 2
            [bd] => 440399
            [nk] => 898020
        )

    [3] => Array
        (
            [mon] => 3
            [bd] => 363543
            [nk] => 878250
        )

)

我已经回答了你的SQL输出。给出了SQL的示例。

<强> PHP

$output_arr = array();
//Your sql
$sql = "select sale_plc
      , month(sale_date) as mon
      , sum(sale_cost) as cost 
from daily_sales 
 where year(sale_date)='2016' 
group 
    by year(sale_date)
      , month(sale_date)
      , sale_plc 
order 
    by month(sale_date)
      , sale_plc asc 
 LIMIT 0, 30";
$tmp = 0;
$i = 0;
$qry = mysqli_query($conn, $sql);
while ($obj = mysqli_fetch_object($qry )){
    if($tmp == 0 || $tmp != $obj->mon)
        $output_arr[$obj->mon][mon] = $obj->mon;
    if($obj->id == 'bd')
        $output_arr[$obj->mon][$obj->id] = $obj->cost;
    if($obj->id == 'nk')
        $output_arr[$obj->mon][$obj->id] = $obj->cost;
    $tmp = $obj->mon;
}

print_r($output_arr);

输出

Array(
[1] => Array
    (
        [mon] => 1
        [bd] => 224787
        [nk] => 721102
    )
[2] => Array
    (
        [mon] => 2
        [bd] => 440399
        [nk] => 898020
    )
[3] => Array
    (
        [mon] => 3
        [bd] => 363543
        [nk] => 878250
    )
)

试试这个答案，如果有任何问题，请告诉我。

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1 个答案: