我有两张表,有很多关系。 产品(ID,描述,价格,图像)----> products_category(idProducts,category _id)----> category(id,category_name)。
以下是我的提示:
1。产品
@Entity
@Table(name = "products")
public class Products implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "idProducts")
private long id;
@Column(name = "description")
private String description;
@Column(name = "price")
private String price;
@Column(name = "image")
private byte [] image;
public Products() {
}
public Products(String description, String price, byte[] image) {}
@ManyToMany
@JoinTable(
name = "category_products",
joinColumns ={@JoinColumn (name = "Products_idProducts", referencedColumnName = "idProducts")},
inverseJoinColumns = {@JoinColumn(name = "category_id", referencedColumnName = "id")}
)
List<Category> categories = new ArrayList<>();
@ManyToMany
@JoinTable(
name = "users_product",
joinColumns ={@JoinColumn (name = "Products_idProducts", referencedColumnName = "idProducts")},
inverseJoinColumns = {@JoinColumn(name = "users_id", referencedColumnName = "id")}
)
List<Users> usersList = new ArrayList<>();
2.Category
@Entity
@Table(name = "category")
public class Category {
@Id
@Column(name = "id")
private long id;
public Category() {
}
public Category(String category_name) {
this.category_name = category_name;
}
@Column (name = "category_name")
private String category_name;
@ManyToMany(mappedBy = "categories")
private List<Products> products = new ArrayList<>();
我正在尝试为控制器编写查询,它通过带有id的先前选择的类别对象返回所有产品?我尝试了很多查询,但都抛出异常。
public List<Products> list (Category category) {
//category - object with needed id
Query query;
query = entityManager.createQuery("SELECT c FROM Category c left join c.categories WHERE c.category = :category", Products.class);
query.setParameter("category", category);
return (List<Products>) query.getResultList();
}
java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: categories of: classes.Category [SELECT c FROM classes.Category c join c.categories WHERE c.category = :category]
org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750)
org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677)
org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683)
答案 0 :(得分:5)
如果您需要检索产品,则需要查询select
产品实体,而不是类别。
所以:
通过预先选择的类别对象返回所有产品 ID
你需要这样做:
Query query = entityManager.createQuery("SELECT p FROM Product p
JOIN p.categories c
WHERE c.id = :idCategory");
query.setParameter("idCategory", category.getId());
您使用LEFT JOIN
但在您的情况下这不是必需的,因为查询的唯一条件是找到具有特定ID的类别。此条件将忽略LEFT
的{{1}}部分,强制始终为JOIN
。
答案 1 :(得分:1)
我认为您的代码中存在一些错误:
SELECT c
表示Category
,但您将结果列表转换为List<Product>
,SELECT c.products
您的WHERE c.category = :category
条款不正确,因为您的类别类中没有category
属性,WHERE c.id = :id
和query.setParameter("id", category.getId());
< / p>
希望有所帮助。