Question

我有一个日期列表。我想插入整数：从第一个星期一到星期日1，从第二个星期一到星期日2等等......

如何在SQL Server中执行此操作？

预期产出：

03/14/16    1
03/15/16    1
03/16/16    1
03/17/16    1
03/18/16    1
03/19/16    1
03/20/16    1
03/21/16    2
03/22/16    2
03/23/16    2
03/24/16    2
03/25/16    2
03/26/16    2
03/27/16    2
03/28/16    3
03/29/16    3
03/30/16    3
03/31/16    3
04/01/16    3
04/02/16    3
04/03/16    3
04/04/16    4

Answer 1

试试这个

SELECT DENSE_RANK() OVER( ORDER BY DATEPART(YEAR,[date column])
,DATEPART(WEEK,[date column]) ) FROM table

Answer 2

与DENSE_RANK

相同的另一种方法

如果您的语言环境没有星期一作为一周的第一天，您可能还需要SET DATEFIRST 1。

SELECT 
 MyDate,
 DATENAME(WEEKDAY, MyDate),
 (DATEPART(WEEK, MyDate) - DATEPART(WEEK,MIN(MyDate) OVER (ORDER BY MyDate)))
 + ((DATEPART(YEAR, MyDate) - DATEPART(YEAR,MIN(MyDate) OVER (ORDER BY MyDate))) *52) + 1 MyWeek
FROM MyData

MyDate                                    MyWeek
---------- ------------------------------ -----------
2015-12-26 Saturday                       1
2015-12-27 Sunday                         1
2015-12-28 Monday                         2
2015-12-29 Tuesday                        2
2015-12-30 Wednesday                      2
2015-12-31 Thursday                       2
2016-01-01 Friday                         2
2016-01-02 Saturday                       2
2016-01-03 Sunday                         2
2016-01-04 Monday                         3
2016-01-05 Tuesday                        3

修改修复年份

编辑2 真正修复年度越过，每个星期一的增量计数器（例如，如果第一个日期是星期几），请参阅示例数据。

Answer 3

DECLARE @start DATE = '2016-03-14'

;WITH cte AS (
SELECT  @start as [d],
        1 as [w]
UNION ALL
SELECT  DATEADD(day,1,[d]),
        CASE WHEN DATEPART(WEEK,[d]) != DATEPART(WEEK,DATEADD(day,1,[d])) THEN w+1 ELSE w END
FROM cte
WHERE d < '2017-04-04')


SELECT [d], [w]
FROM cte
OPTION (MAXRECURSION 1000)

增量插入SQL列

3 个答案: