Question

考虑以下代码：

    <?php


function absolute_url($page = 'Index.php')
{
    //header('Location: http:\\localhost');
    //exit(); //terminates the script

    $url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']);
    $url = rtrim($url, '/\\');
    $url .= '/' . $page;

    return $url;
}

function checkLogin($Email = '', $password = '')
{
  $errors = array();

  if(empty($Email))
    $errors[] = 'You must enter a Email';

  if(empty($password))
    $errors[] = 'You must enter a password';

  if(empty($errors))
  {
////set up database econnection
     include 'DBConn.php';

      $db = new DBConn();
      $dbc = $db->getDBConnection();

      $q = "select Email, FName, LName from Users_1 where Email = '$Email' and Password = '$password'";

      $r = mysqli_query($dbc, $q);

      if($r)
      {
          if(mysqli_affected_rows($dbc) != 0)
          {
            $row = mysqli_fetch_array($r, MYSQLI_ASSOC);
            return array(true, $row);
          }
          else
          {
            $errors[] = 'Passwords do not match';
          }
      }
      else{
        echo '<p class="error"> Oh dear. There was a database error</p>';
        echo '<p class = "error">' . mysqli_error($dbc) .'</p>';
      }

  }

  return array(false, $errors);
}
?>

此程序将两个客户端连接作为不同的线程接受，并在每个线程的处理程序类中运行class program { public static ConcurrentDictionary<string, int> dictionary = new ConcurrentDictionary<string,int>(); static void Main(string[] args) { runServer(); } static void runServer() { //Server setup Handler threadRequest; Thread[] threadsArray = new Thread[2]; int i = 0; while(true) { Socket connection; connection = listener.AcceptSocket(); threadRequest = new Hander(); threadsArray[i] = new Thread(() => threadRequest.clientInteraction(connection, dictionary)); threadsArray[i].Start(); i++; } } } class Handler { public void clientInteraction(Socket connection, ConcurrentDictionary<string, int> dictionary) { NetworkStream socketStream; socketStream = new NetworkStream(connection); StreamWriter sw = new StreamWriter(socketStream); StreamReader sr = new StreamReader(socketStream); parseStrings(out pTeamName); //checks to see if its a valid "add team" request dictionary.tryAdd(pTeamName, 0); while(dictionary.Count < 2) { //hang until two teams } sw.WriteLine("Welcome To The Game."); sw.Flush(); foreach(KeyValuePair<string, int> kvp in dictionary) { Console.WriteLine("Team: {0}", kvp.Key); } foreach(KeyValuePair<string, int> kvp in dictionary) { sw.WriteLine("Team: {0}", kvp.Key); sw.Flush(); } } }方法。我担心的是，如果两个线程同时命中clientInteraction，服务器将无法执行它。

我推断这是因为服务器没有打印＆＃34;欢迎来到游戏＆＃34;到任一客户端，只打印一个sw.Flush()（同一条目）的条目到两个客户端，省略一个。

从调试和dictionary到服务器控制台，我知道字典已正确填充。我很困惑为什么给客户的写作不起作用。

欢迎任何帮助，如果我遗漏任何重要内容，请告知我们。提前谢谢。

编辑：无论出于何种原因，似乎每个人都有其他的＆＃39;一套冲洗工作。例如我放了：

Console.WriteLine

在foreach循环下方将字典打印到客户端。前两个while(true) { sw.WriteLine("BOO"); sw.Flush(); Console.ReadKey(); }打印＆＃34; BOO＆＃34;到其中一个客户端（取决于哪个线程是第一个），然后两个客户端什么都不做。接下来的两个打印＆＃34; BOO＆＃34;再次。我并不特别希望使用i = 2 ReadKeys循环对每个sw.Flush()进行框架化，以使其正常工作。

Answer 1

确保没有任何单独的连接同时执行操作不是您的责任。您需要确保不同时使用/访问来自多个线程的单个连接，但操作系统有责任确保不同连接的操作不会相互影响

线程及其与Concurrent Dictionary和sw.Flush（）的交互;

1 个答案: