Question

是否可以使用Codeigniter的Active Record CI2使用JOINed表更新数据？我有运行代码，我想转换为Codeigniter的Active Record。

public function update_table($job_id, $om_id, $recipient_id)
{
    $query = "UPDATE table1 AS t1
                       INNER JOIN table2 AS t2
                               ON t1.om_id = t2.id
                SET    t2.read_date = NOW()
                WHERE  t2.ref_table_id = $job_id
                AND    t1.om_id = $om_id
                AND    t2.recipient_id = $recipient_id
                AND    t2.read_date = '0000-00-00 00:00:00'";

    $result = $this->db->query($query);
    return $result;
}

我尝试这样但不起作用。

public function update_table($job_id, $om_id, $recipient_id)
{
    $this->db->set('t2.read_date', NOW());

    $this->db->where('t2.ref_table_id', $job_id);
    $this->db->where('t1.om_id', $om_id);
    $this->db->where('t2.recipient_id', $recipient_id);
    $this->db->where('t2.read_date', '0000-00-00 00:00:00');
    $this->db->where('t2.om_id = t1.id');
    $this->db->update('table1 AS t1, table AS t2');

}

任何帮助将不胜感激。感谢

Answer 1

你可以试试吗..

将$ condition作为数组提供...与您想要更新的数据相同。

function update_data($table, $data, $condition)
{
    $this->db->where($condition);
    $this->db->update($table, $data); 
}

如何使用Codeigniter的Active Record CI2使用JOINed表更新数据？

1 个答案: