使用group_concat

Question

我有一个名为LOPList的表：

a busy cat http://i65.tinypic.com/11c60co.png

我希望结果如下：

LOPID | EMP ID | TIME START (LOPStatus = 'Y') | TIME END (LOPStatus = 'N')

2     | 6      | 2016-03-24T20:05:27+00:00    | 2016-03-24T20:14:41+00:00

5     | 6      | 2016-03-24T20:07:59+00:00    | 2016-03-24T20:13:11+00:00

Answer 1

尝试：

select LOPID,EmpId,
max(case when LOPStatus='Y' then TimeUpdated end) as time_start,
max(case when LOPStatus='N' then TimeUpdated end) as time_end  
from LOPList where JobID= 22 group by LOPID;

Answer 2

SELECT list.LOPID，list.EmpID as＆＃34; EMP ID＆＃34;， listY.TimeUpdated as＆＃34; TIME START（LOPStatus =＆＃39; Y＆＃39;）＆＃34 ;, listN.TimeUpdated as＆＃34; TIME END（LOPStatus =＆＃39; N＆＃39;）＆ ＃34; from（SELECT DISTINCT LOPID，EmpID FROM [TestDB]。[dbo]。[LOPList]）AS列表， （从[TestDB]中选择LOPID，LOPStatus，TimeUpdated。[dbo]。[LOPList]其中LOPStatus =＆＃39; Y＆＃39;）listY， （从[TestDB]中选择LOPID，LOPStatus，TimeUpdated。[dbo]。[LOPList]其中LOPStatus =＆＃39; N＆＃39;）listN  WHERE listY.LOPID = list.LOPID和listN.LOPID = list.LOPID;

你应该知道一些sql语言的besic知识，在这里你应该使用＆＃39; DISTINCT＆＃39;声明，谢谢，希望能带给你一些帮助