Question

所以我试图运行这个的轨道c：

Borrower.update(1, raised: 0)

和此：

Borrower Load (0.3ms)  SELECT  "borrowers".* FROM "borrowers" WHERE "borrowers"."id" = $1 LIMIT 1  [["id", 1]]

(0.2ms)  BEGIN
Borrower Exists (0.5ms)  SELECT  1 AS one FROM "borrowers" WHERE (LOWER("borrowers"."email") = LOWER('j@kay.com') AND "borrowers"."id" != 1) LIMIT 1

(0.2ms)  ROLLBACK

"table with raised = 0"
1 row in set

我得到了回滚：

class Borrower < ActiveRecord::Base
has_many :lenders
has_many :histories, dependent: :destroy
has_many :borrowed_from, through: :histories, source: :lender
EMAIL_REGEX = /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]+)\z/i
validates :first_name, :last_name, :email, :purpose, :description, :money, presence: true
validates :email, uniqueness: {case_sensitive: false}, format: {with: EMAIL_REGEX}

has_secure_password
end

这是我的“借款人”模型：

create_table "borrowers", force: :cascade do |t|

t.string   "first_name"
t.string   "last_name"
t.string   "email"
t.string   "password_digest"
t.integer  "money"
t.string   "purpose"
t.text     "description"
t.integer  "raised"
t.datetime "created_at",      null: false
t.datetime "updated_at",      null: false
end

和我的架构：

int * objects = (int *)malloc(amount_of_objects * 7 * sizeof(int));
if (x_vector != 0 || y_vector != 0 || z_vector != 0) {
for (int j = 0; j < amount_of_objects; ++j) {
    *(objects + (j * 4)) = j;
    *(objects + (j * 4 + 1)) = x_start;
    *(objects + (j * 4 + 2)) = y_start;
    *(objects + (j * 4 + 3)) = z_start;
    *(objects + (j * 4 + 4)) = x_vector;
    *(objects + (j * 4 + 5)) = y_vector;
    *(objects + (j * 4 + 6)) = z_vector;
}`

如何永久更新“凸起”？

Answer 1

验证失败，尝试在您的控制台上打印验证错误：

borrower = Borrower.update(1, raised: 0)
puts borrower.errors

如果您想明确跳过验证，另一种解决方案可能是update_attribute：

Borrower.find(1).update_attribute(:raised, 0)

如果您还想跳过回调并避免触及updated_at，那么update_column：

Borrower.find(1).update_column(:raised, 0)

如果raised是一种布尔属性，您也可以选择toggle!：

Borrower.find(1).toggle!(:raised)

Rails c sql命令是回滚而不是更新

1 个答案: