Question

我想序列化属性，但每个属性都包含在一个单独的JSON对象中。

以下示例：

public class Metadata
{
    public string Name { get; set; }
    public Guid Id { get; set; }
}

public void SerializeCars()
{
    var data = new Metadata { Name = "MyName", Id = Guid.NewGuid() };
    var json = JsonConvert.SerializeObject(data, Formatting.Indented);
}

目前的结果将是：

{
    "Name": "MyName",
    "Id": "f9c4bc06-0b99-47ff-b22b-ea094fc188ee"
}

我希望它（上面缺少“td”类）：

{
    "td": [{
        "name": "myName"
    }, {
        "id": "f9c4bc06-0b99-47ff-b22b-ea094fc188ee"
    }]
}

可以修复吗？

Answer 1

您可以创建自定义JsonConverter以获得所需的输出：

class MetadataConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return (objectType == typeof(Metadata));
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        JArray array = new JArray();
        foreach (PropertyInfo pi in value.GetType().GetProperties().Where(p => p.CanRead))
        {
            array.Add(new JObject(new JProperty(pi.Name, pi.GetValue(value, null))));
        }
        JObject obj = new JObject(new JProperty("td", array));
        obj.WriteTo(writer);
    }

    public override bool CanRead
    {
        get { return false; }
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }

}

然后，像这样使用它：

var json = JsonConvert.SerializeObject(data, Formatting.Indented, new MetadataConverter());

小提琴：https://dotnetfiddle.net/5IRDeu

Answer 2

如果需要它以这种方式序列化，请尝试对序列化字符串进行一些后处理。请记住，在反序列化之前，如果没有一些处理，这将不会反序列化。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using Newtonsoft.Json;
using Newtonsoft;
using Newtonsoft.Json.Linq;

namespace ConsoleApplication1
{

    public class Metadata
    {
        public string Name { get; set; }
        public Guid Id { get; set; }
    }

    public class Root
    {
        public List<Metadata> listOfMetadata{get;set;}
    }

    class Program
    {
        static void Main(string[] args)
        {
            Run run = new Run();
            run.SerializeCars();
        }
    }

    public class Run
    {
        public void SerializeCars()
        {
            var root = new Root()
            {
                listOfMetadata = new List<Metadata>()
                {
                    new Metadata
                    { 
                        Name = "MyName", Id = Guid.NewGuid()
                    }
                }
            };

            var json = JsonConvert.SerializeObject(root, Formatting.Indented);
            json = json.Replace("\"listOfMetadata\": ", string.Empty);
            Console.WriteLine(json);
            Console.ReadKey();
        }
    }
}

序列化对象的属性以分离数组中的JSON对象

2 个答案: