Question

正如标题所述，我希望将内容打印成两列，但我似乎遇到了错误。

int noOfHorseInList = 7;
        String horseName[] = {"Blitz", "Sparky", "Sandy", "Rolo", "Beano", 

"Flash", "", "", ""};
        int horseAge[] = {2, 4, 1, 4, 4, 2, 0, 0, 0};
        int timeTakenInSeconds[] = {600, -1, 500, 430, 412, -1, 0, 0, 0};

    int option = 0;

    System.out.println("Please choose from the following selection");
    System.out.println("1. Show horses that finished\n2. Show horse details\n3. Adding a Late Entrant");
    option = kb.nextInt();
    kb.hasNextLine();

    switch(option)
    {
    case 1:
        //Finishers
        String showHorseThatFinished = "";
        showHorseThatFinished = finishers(noOfHorseInList, horseName, timeTakenInSeconds);

        String timeOfHorse = "";

        for(int i = 0; i < noOfHorseInList; i++)
        {
            if(timeTakenInSeconds[i] > -1)
            {
                timeOfHorse = timeOfHorse + "\n" + timeTakenInSeconds[i];
            }
        }


        System.out.println("Horses Name\tFinishing Time");
        System.out.println(showHorseThatFinished + "\t" + timeOfHorse);



        break;

    case 2:
        //Horse details





        break;

    case 3:
        //Adding Late Entrant



        break;

    }

}

public static String finishers(int noOfHorseInList,String horseName[],int timeTakenInSeconds[])
{
    String showHorseThatFinished = "";

    for(int i = 0; i < noOfHorseInList; i++)
    {
        if(timeTakenInSeconds[i] > -1)
        {
            showHorseThatFinished = showHorseThatFinished + "\n" + horseName[i];
        }
    }


    return showHorseThatFinished;
}

这是我的输出，我希望将值分成两列彼此

Answer 1

在相同的功能中添加马的名称和时间。

使用StringBuffer进行追加。效率更高。

public static String finishers(int noOfHorseInList,String   horseName[],int timeTakenInSeconds[]) {
StringBuffer showHorseThatFinished = new StringBuffer();

for(int i = 0; i < noOfHorseInList; i++) {
        // You need all horses to be written. Mark somehow that their time is erroneous
        String time = "ERROR";    

        if (timeTakenInSeconds[i] > -1) {
              time = "" + timeTakenInSeconds[i];
        }

        showHorseThatFinished.append(horseName[i]);
        showHorseThatFinished.append("\t");
        showHorseThatFinished.append(time);
        showHorseThatFinished.append("\n");
    }
}

    return showHorseThatFinished.toString();
}

不再需要这段代码

    String timeOfHorse = "";

    for(int i = 0; i < noOfHorseInList; i++)
    {
        if(timeTakenInSeconds[i] > -1)
        {
            timeOfHorse = timeOfHorse + "\n" + timeTakenInSeconds[i];
        }
    }

只需

  System.out.println(showHorseThatFinished);

Answer 2

你实际上计算得太多了......

看看这个方法：
终结者（int noOfHorseInList，String horseName []，int timeTakenInSeconds []）

像这样修改：

public static String finishers(int noOfHorseInList, String horseName[], int timeTakenInSeconds[]) {
        String showHorseThatFinished = "";

        for (int i = 0; i < noOfHorseInList; i++) {
            if (timeTakenInSeconds[i] > -1) {
                showHorseThatFinished = showHorseThatFinished + "\n" + horseName[i] + "\t\t\t" + timeTakenInSeconds[i];
            }
        }
        return showHorseThatFinished;

    }

并且您的表格将在不需要

的情况下完成

for(int i = 0; i < noOfHorseInList; i++)
        {

案例1

中的

Answer 3

如何将for循环中的以下行更改为 -

graph=None

将结果打印成两列错误的java

3 个答案: