Question

我需要制作月度访问报告，进一步细分为每个月的每周摘要。我有一个SQL结果数组，其中包含月份编号，周编号以及周开始日期和结束日期。

Month   Week    week start  weekend
1       1       12/27/2015  1/2/2016
1       2       1/3/2016    1/9/2016
...
2       6       1/31/2016   2/6/2016
2       7       2/7/2016    2/13/2016

如果它们都是同一个月的一部分，我想遍历这个数组并为每周创建表。然后在月末，回显月度汇总表，然后移动下个月。以下是一些示例代码：

while ($weekarr=odbc_fetch_array($weekresult))
{

  $week1 = date('m.d.Y', strtotime($weekarr['weekstart']));
  $week2 = date('m.d.Y', strtotime($weekarr['weekend']));

  if ($weekarr['month']==$i)
   {


     echo "<table border='1' style='float: left' width=1 cellpadding='5'>";
     echo "<tr style='background-color:#484848;color:white'><td   colspan='4'>Week&nbsp;of&nbsp;".$week1."&nbsp;to&nbsp;".$week2;
     echo "<tr><td>Membership</td><td>Visitors</td><td>Purchased</td> <td>Comped</td></tr>";
   }//end if

  else
   { echo monthly table
     $i++;
   }
} //end while

1月结束后（月份= 1），每个新月的第一周都会被跳过。如何在不跳过每月第一周的情况下增加$ i？

Answer 1

    while ($weekarr=odbc_fetch_array($weekresult))
    {

      $week1 = date('m.d.Y', strtotime($weekarr['weekstart']));
      $week2 = date('m.d.Y', strtotime($weekarr['weekend']));

      if ($weekarr['month']==$i)
       {


         echo "<table border='1' style='float: left' width=1 cellpadding='5'>";
         echo "<tr style='background-color:#484848;color:white'><td   colspan='4'>Week&nbsp;of&nbsp;".$week1."&nbsp;to&nbsp;".$week2;
         echo "<tr><td>Membership</td><td>Visitors</td><td>Purchased</td> <td>Comped</td></tr>";
       }//end if

      else
       { echo monthly table
         echo "<table border='1' style='float: left' width=1 cellpadding='5'>";
         echo "<tr style='background-color:#484848;color:white'><td   colspan='4'>Week&nbsp;of&nbsp;".$week1."&nbsp;to&nbsp;".$week2;
         echo "<tr><td>Membership</td><td>Visitors</td><td>Purchased</td> <td>Comped</td></tr>";
         $i++;
       }
    } //end while

基本上，您希望在失败条件

中为该一周的成功条件运行输出

如何使用if / else语句迭代sql结果数组？

1 个答案: