由于我的dataBase的复杂性,我决定创建一个新的Object,我只指定我将使用的参数。要进行自定义查询,我在JPA中使用createNativeQuery。跟随我的对象。
POJO:
@Entity
public class Unidade implements Serializable{
private static final long serialVersionUID = 1L;
private Long numeroUnidade;
private String nomeUnidade;
private Integer numeroCep;
private Integer numeroCepComplemento;
private String tipoServico;
private Integer status;
private String logradouro;
private String bairro;
private String cidade;
private String uf;
private Integer statusVinculo;
//getter and setters
目前我正在使用以下select来返回简单整数并且在没有显示任何问题的情况下工作。
@PersistenceContext(unitName="projetoAtividade")
private EntityManager em;
public void selectTeste(){
int quantidade = (Integer) em.createNativeQuery("select count(*) from abc.nattbu29_escritorio;").getSingleResult();
System.out.println("========== QUANTIDADE DE REGISTRO NA TABELA ===========");
System.out.println(quantidade);
}
虽然前面的查询运行正常,但是当提交一个复杂的查询放置相应的别名时,使用createNativeQuery并将对象返回,hibernate抛出一个异常(org.hibernate.MappingException:Unknown)。
记住我创建了一个新的类,将@Entity指定为。
查询:
@SuppressWarnings("unchecked")
public List<UnidadeTeste> buscarUnidadeGenerica(int numeroCeps, int numeroComplementoCeps){
List<UnidadeTeste> lsita = new ArrayList<UnidadeTeste>();
String query = "SELECT "
+"TBZ21.NATURAL as numeroPv, "
+"TBZ21.UNIDADE as nomePv, "
+"TBZ21.SITUACAO as statusVinculacao, "
+"TBJ55.TPO_ATUACAO_U44 as tipoServAZW, "
+"TBJ55.SITUACAO_ATUAL as status, "
+"TBH18.LOCALIDADE as cidade, "
+"'' as bairro, "
+"'' as logradouro, "
+"TBH18.CEP as numeroCep, "
+"TBH18.CEP_COMPLEMENTO as numeroCepComplemento, "
+"TBH18.FK_AZWVWL22_UNISG as uf "
+"FROM AZW.AZWTBJ55_RGATUACAO TBJ55 "
+"LEFT JOIN AZW.AZWTBH18_LOCALIDADE TBH18 ON "
+"TBH18.LOCALIDADEE = TBJ55.LOCALIDADEE "
+"LEFT JOIN AZW.AZWTBZ21_UNIDADE TBZ21 ON "
+"TBJ55.NATURAL = TBZ21.NATURAL "
+"WHERE TBH18.CEP = ?1 "
+"AND TBH18.CEP_COMPLEMENTO = ?2; "
lsita = em.createNativeQuery(query, Unidade.class)
.setParameter(1, numeroCeps)
.setParameter(2, numeroComplementoCeps)
.getResultList();
System.out.println(lsita.size()+"<<<<=====================");
return lsita;
}
错误:
Caused by: org.hibernate.MappingException: Unknown entity: br.com.project.modelo.UnidadeTeste
at org.hibernate.internal.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:1031) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.loader.custom.sql.SQLQueryReturnProcessor.getSQLLoadable(SQLQueryReturnProcessor.java:336) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.loader.custom.sql.SQLQueryReturnProcessor.processRootReturn(SQLQueryReturnProcessor.java:377) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.loader.custom.sql.SQLQueryReturnProcessor.processReturn(SQLQueryReturnProcessor.java:356) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.loader.custom.sql.SQLQueryReturnProcessor.process(SQLQueryReturnProcessor.java:172) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.loader.custom.sql.SQLCustomQuery.<init>(SQLCustomQuery.java:87) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.engine.query.spi.NativeSQLQueryPlan.<init>(NativeSQLQueryPlan.java:67) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.engine.query.spi.QueryPlanCache.getNativeSQLQueryPlan(QueryPlanCache.java:155) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.internal.AbstractSessionImpl.getNativeSQLQueryPlan(AbstractSessionImpl.java:218) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.internal.AbstractSessionImpl.list(AbstractSessionImpl.java:224) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.internal.SQLQueryImpl.list(SQLQueryImpl.java:156) [hibernate-core-4.0.1.Final.jar:4.0.1.Final]
at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:252) [hibernate-entitymanager-4.0.1.Final.jar:4.0.1.Final]
... 84 more
在我的互联网搜索中,几乎所有论坛主题在解决方案答案中都是一致的:“在课前声明中放置@Entity”但是,这对我不起作用。
我一整天都在“花费”努力寻找可行的解决方案但不幸的是, 我没有成功。有人可以说一种解决我问题的新方法吗? 我在2个不同的项目中进行了测试,并且遇到了同样的问题。
问题补充:
伙计们,我试过在我的类中创建一个@SqlResultSetMapping,编码如下,但是现在,hibernate还是另外一个例外:
ERROR [org.jboss.ejb3.invocation] (http--127.0.0.1-8888-2) JBAS014134: EJB Invocation failed on component AtividadeEJB for method public void br.com.project.jboss.modelo.AtividadeEJB.testeChamada(): javax.ejb.EJBException: javax.persistence.PersistenceException: org.hibernate.MappingException: Unknown SqlResultSetMapping [UnidadeResult]
at org.jboss.as.ejb3.tx.CMTTxInterceptor.handleExceptionInOurTx(CMTTxInterceptor.java:166) [jboss-as-ejb3-7.1.1.Final.jar:7.1.1.Final]
at org.jboss.as.ejb3.tx.CMTTxInterceptor.invokeInOurTx(CMTTxInterceptor.java:230) [jboss-as-ejb3-7.1.1.Final.jar:7.1.1.Final]
at org.jboss.as.ejb3.tx.CMTTxInterceptor.required(CMTTxInterceptor.java:304) [jboss-as-ejb3-7.1.1.Final.jar:7.1.1.Final]
at org.jboss.as.ejb3.tx.CMTTxInterceptor.processInvocation(CMTTxInterceptor.java:190) [jboss-as-ejb3-7.1.1.Final.jar:7.1.1.Final]
at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:288) [jboss-invocation-1.1.1.Final.jar:1.1.1.Final]
我的新POJO:
@Entity
@SqlResultSetMapping(name="UnidadeResult",
entities={
@EntityResult(entityClass=UnidadeTeste.class, fields={
@FieldResult(name="tx_descricao", column="nomePv"),
@FieldResult(name="nu_idntr_pessoa", column="id")})},
columns={
@ColumnResult(name="nomePv")}
)
public class UnidadeTeste implements Serializable{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private Long id;
private String nomePv;
public String getNomePv() {
return nomePv;
}
public void setNomePv(String nomePv) {
this.nomePv = nomePv;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
我的EJB:
@SuppressWarnings("unchecked")
public void testeChamada(){
List<Object> lista = em.createNativeQuery("SELECT nu_idntr_pessoa as id, email as nomePv FROM pessoa;", "UnidadeResult").getResultList();
System.out.println("===============>>"+lista.size());
}
答案 0 :(得分:0)
如果您想将原始查询的结果返回给我建议使用SqlResultSetMapping的对象。
否则,请将您的返回类型设置为:
List<Object[]> results = em.createNativeQuery(query)
.setParameter(1, numeroCeps)
.setParameter(2, numeroComplementoCeps)
.getResultList();
然后遍历结果列表,并将Object数组的每个成员转换为其数据类型。
答案 1 :(得分:0)
列表与LT;的 UnidadeTeste 强>&GT; lsita = new ArrayList&lt; UnidadeTeste &gt;();
lsita = em.createNativeQuery(查询, Unidade .class)
此处存在类型不匹配。例外情况很明显:未知实体:br.com.project.modelo。 UnidadeTeste
您的实体是Unidade,您必须返回List<Unidade>
而不是UnidadeTeste
。
否则请尝试SqlResultSetMapping
答案 2 :(得分:0)
我的解决方案是:
在此主题中:How to map a Native Query to a POJO, when I do not have any Entity on my project? 正好描述了我的问题。但即便阅读之前,我也无法理解一些细节,这解决了我的问题。
甚至为我的查询结果创建一个接收器的简单实体,将我的类映射到persistence.xml是必要的。这是我的错误!
所以,我的项目现在:
的persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="projetoAtividade" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>java:/projetoAtividade</jta-data-source>
//another classes
<class>br.com.project.modelo.UnidadeTeste</class>
//properties of connection
UnidadeTeste.class:
package br.com.project.modelo;
import javax.persistence.Entity;
import javax.persistence.Id;
@Entity
public class UnidadeTeste {
@Id
private Long id;
private String description;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
}
EJB:
@SuppressWarnings("unchecked")
public void testeChamada(){
List<UnidadeTeste> lista = em.createNativeQuery("SELECT nu_idntr_pessoa AS id, email AS description FROM Pessoa", UnidadeTeste.class).getResultList();
System.out.println("===============>>"+lista.size());
}
请记住,您需要在类中创建的属性上为具有相同名称的列添加别名。