Question

我正在开发一个java项目，我在eclipse下有一个动态的web项目，接收请求和处理文件上传，现在一切都还可以，但我想存储上传的文件，以便能够托管我的文件，例如，当我把这个样本网址录下来时，我想要那个：

本地主机：18080 /上传/ img.jpg

在浏览器中我可以看到屏幕上的图像。这就是我所拥有的项目结构： project structure

我有一个REST资源，我没有使用servlet级别，我的应用程序部署在wildfly而不是tomcat，

这里我的Rest资源向您展示代码：

package rest;

import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.URISyntaxException;
import java.net.URL;
import java.util.List;
import java.util.Map;

import javax.faces.bean.RequestScoped;
import javax.ws.rs.Consumes;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.MultivaluedMap;
import javax.ws.rs.core.Response;

import sun.misc.IOUtils;

import org.jboss.resteasy.plugins.providers.multipart.InputPart;
import org.jboss.resteasy.plugins.providers.multipart.MultipartFormDataInput;

@RequestScoped
@Path("uploader")
public class UploadResource {

private final String UPLOADED_FILE_PATH = "d:\\";
@POST
@Path("/upload")
@Consumes("multipart/form-data")
@Produces(MediaType.APPLICATION_JSON)
public UploadResponse uploadFile(MultipartFormDataInput input)
        throws URISyntaxException {

    String fileName = "";
    UploadResponse uploadResponse = null;
    Map<String, List<InputPart>> uploadForm = input.getFormDataMap();
    List<InputPart> inputParts = uploadForm.get("uploadedFile");
    for (InputPart inputPart : inputParts) {
        MultivaluedMap<String, String> header = inputPart.getHeaders();
        fileName = getFileName(header);
        // convert the uploaded file to inputstream
        InputStream inputStream;
        try {
            inputStream = inputPart.getBody(InputStream.class, null);
            byte[] bytes = IOUtils.readFully(inputStream, 0, false);                
            fileName = UPLOADED_FILE_PATH + fileName;
            uploadResponse = new UploadResponse(fileName);
            writeFile(bytes, fileName);
            System.out.println("Done");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return uploadResponse;
}

private void writeFile(byte[] content, String fileName) throws IOException {

    String url = this.getClass().getResource("/slide-1.jpg").toString();
    System.out.println("url" + url);

    /*
     * URL url = this.getClass().getResource("/"); System.out.println("url"
     * + url); File fullPathToSubfolder = new File(url.toURI())
     * .getAbsoluteFile(); String projectFolder =
     * fullPathToSubfolder.getAbsolutePath() .split("target")[0]; fileName =
     * projectFolder + "WebContent/uploads/resources/";
     */

    File file = new File(fileName);
    if (!file.exists()) {
        file.createNewFile();
    }

    FileOutputStream fop = new FileOutputStream(file);

    fop.write(content);
    fop.flush();
    fop.close();

}

private String getFileName(MultivaluedMap<String, String> header) {

    String[] contentDisposition = header.getFirst("Content-Disposition")
            .split(";");

    for (String filename : contentDisposition) {
        if ((filename.trim().startsWith("filename"))) {

            String[] name = filename.split("=");

            String finalFileName = name[1].trim().replaceAll("\"", "");
            return finalFileName;
        }
    }
    return "unknown";
}

}

请帮助我，我对此问题感到困惑。

将上传的图像放在浏览器中的位置

0 个答案: