Question

在文档审阅工具中，可以创建＆＃34;批次＆＃34;的文件。批处理是一组相关文档，由GroupID标识。

这些文档组将提供给审阅者，审阅者更新名为Testcompleted的字段。该字段有3种可能的状态：1,0或null。组中的文档数量各不相同。

在下面的示例中，我有3组（＆＃34;批次＆＃34;）文档。例如，第一批（batch_0001）有2个文件（58和59）。

#Document

ArtifactID    Testcompleted    GroupID
--------------------------------------
58            1                4
59            1                4
60            null             6
61            1                6
62            null             7
63            null             7
64            null             7

#DocumentBatch

BatchArtifactID    DocumentArtifactID
-------------------------------------
66                 58
66                 59
67                 60
67                 61
68                 62
68                 63
68                 64


#Batch

ArtifactID    Name
------------------------
66            batch_0001
67            batch_0002
68            batch_0003

我需要知道批处理何时完成 - 即：当该批处理中的所有文档都将Testcompleted字段设置为1.在示例中，这是batch_0001的情况。

我正在寻找的输出是：

batch           documents       reviewed     completed
------------------------------------------------------
batch_0001      2               2            yes
batch_0002      2               1            no
batch_0003      3               0            no

我开始加入表格：

select
    *
from
    #Document d

    left join #DocumentBatch db
    on db.DocumentArtifactID = b.ArtifactID

    left join #Batch b
    on db.BatchArtifactID = b.ArtifactID
where
    d.Testcompleted = 1
;

这显然不会返回我需要的结果，但我被卡住了。如何解决这个问题的一些帮助将非常感激。

Answer 1

您可以尝试这样的事情：

select b.name
     , count(*) as documents
     , sum(d.Testcompleted) as reviewed
     , (case when count(*) = sum(d.Testcompleted) then 'yes' else 'no' end) as completed
from [#Document] d
join [#DocumentBatch] db on db.DocumentArtifactID = d.ArtifactID
join [#Batch] b on db.BatchArtifactID = b.ArtifactID
group by b.name

SQLFiddle

count(*)包括计算所有值;
sum(d.Testcompleted)仅计算Testcompleted为1;

Answer 2

您想要的是聚合，因此您需要group by。像这样：

select b.name as batchname, count(d.ARtifactID) as numdocuments,
       sum(case when d.testCompleted = 1 then 1 else 0 end) as NumCompleted,
       (case when sum(case when d.testCompleted = 1 then 0 else 1 end) > 0
             then 'No'
             else 'Yes'
        end) as AllCompleted
from #Batch b left join
     #DocumentBatch db     
     on db.BatchArtifactID = b.ArtifactID
     #Document d left join
     on db.DocumentArtifactID = b.ArtifactID left join
group by b.name;

我认为不需要外连接。您应该可以使用inner join，除非有批次没有文档。如果您确实使用外部联接，则从#Batch开始比#Document更有意义，因为您在批次级别聚合。

Answer 3

select
    b.name, 
    count(db.DocumentArtifactID) as documents,
    -- count only completed
    count(case when d.Testcompleted = 1 then d.ArtifactID end) as reviewed,
    -- if the minimum = 1 there's no 0 or NULL
    case when min(cast(Testcompleted as tinyint)) = 1 then 'yes' else 'no' end as completed
from
    #Batch b

    left join #DocumentBatch db
    on db.BatchArtifactID = b.ArtifactID

    left join #Document d
    on db.DocumentArtifactID = d.ArtifactID
group by b.name;

如果没有丢失的行，您可以切换到内部联接...

如果组中的所有文档的值都设置为1，如何计算？

3 个答案: