Question

我有5个字符串文本（在.txt文件中）：

{BANANAS} 2015/02/03 16:10 - Old look - Old Design
{BALOONS} 2015/02/03 16:23 - New look - New Design
{ORANGES} 2015/02/03 16:30 - Old look - Old Design
{BALOONS} 2015/02/03 16:50 - New look - New Design
{CARS} 2015/02/03 16:55 - New link - New Creation

我需要php脚本，只输出：

New look - New Design
New look - New Design
New link - New Creation

我有这个脚本 - 但它有 2 问题：

1）它只适用于一种类型的字符串 - 文本{BALOONS}; 2）它仅输出＆＃34;新设计＆＃34;，但我需要＆＃34;新面貌 - 新设计＆＃34;。

<?php
$search = 'New look';
$search2 = 'New link';
$lines = file('myfile.txt');


$found = false;
foreach($lines as $line)
{
  if(strpos($line, $search) !== false || strpos($line, $search2) !== false)
  {
$found = true;
echo preg_replace('/{BALOONS} (.*) - /','',$line) ."<br><br>";
  }
}


if(!$found)
{
  echo 'No match found';
}
?>

谢谢！

Answer 1

您的模式不正确，您可以尝试按照

$src        = '{BANANAS} 2015/02/03 16:10 - Old look - Old Design
              {BALOONS} 2015/02/03 16:23 - New look - New Design
              {ORANGES} 2015/02/03 16:30 - Old look - Old Design
              {BALOONS} 2015/02/03 16:50 - New look - New Design
              {CARS} 2015/02/03 16:55 - New link - New Creation';
$pattern    = '#\{[A-Z]+\} [0-9]{4,4}/[0-9]{2,2}/[0-9]{2,2} [0-9]{2,2}:[0-9]{2,2} - (New [A-Za-z]+ - New [A-Za-z]+)#';

preg_match_all($pattern, $src, $matches);
print_r ($matches);

<强>输出

Array
(
    [0] => Array
        (
            [0] => {BALOONS} 2015/02/03 16:23 - New look - New Design
            [1] => {BALOONS} 2015/02/03 16:50 - New look - New Design
            [2] => {CARS} 2015/02/03 16:55 - New link - New Creation
        )

    [1] => Array
        (
            [0] => New look - New Design
            [1] => New look - New Design
            [2] => New link - New Creation
        )

)

Answer 2

要使示例中的每一行与模式匹配并仅返回所需的字符串，您只能使用一种模式：

$pattern = '
~
    ^           # start of line
    {\w+}       # any word character wrapped by curly brackets
    \s\S+       # space followed by one or more Not-spaces
    \s\S+       # space followed by one or more Not-spaces
    \s-\s       # space-dash-space
    (           # --First match group:
    New\s\w+    #   ‘New’ followed by space and one or more word chars
    \s-\s       #   space-dash-space
    New\s\w+    #   ‘New’ followed by space and one or more word chars
    )           # --END First match group
    \s*         # one-or-more spaces (you can remove this, I think)
    $           # end of line
~mx
';

/* Usage: */
preg_match_all( $pattern, $string, $matches );
echo implode( PHP_EOL, $matches[1] ) . PHP_EOL;

将打印：

New look - New Design
New look - New Design
New link - New Creation

的 regex101 demo

相反，如果您想要在行中检索任何“新事物”，独立的位置，您可以使用：

$pattern = ' ~ ( # --First match group: ( # --Second match group: (New\s\w+) # --3rd match group: ‘New’ followed by space and one-or-more word chars (\s-\s)? # --4st match group: optional space-dash-space )+ # --END Second match group (repeating one-or-more) ) # --END First match group ~mx '; /* Usage: */ preg_match_all( $pattern, $string, $matches ); echo implode( PHP_EOL, $matches[0] ) . PHP_EOL;

您可能希望搜索变量，而不是搜索固定字符串。为此，只需将New替换为{$variable}，就像在此示例中一样：

$find = 'Old'; $pattern = "~^{\w+}\s\S+\s\S+\s-\s({$find}\s\w+\s-\s{$find}\s\w+)\s*$~m"; // ------- -------

（上面的模式与第一个例子相同，在一行中）。

编辑：

要将上述模式应用于原始foreach内的每一行，只需删除第一个匹配组，您的preg_replace即可使用：

$pattern = '~^{\w+}\s\S+\s\S+\s-\s+~'; // no multiline option needed echo preg_replace( $pattern, '', $line ) . '<br><br>;

多个preg_replace规则

2 个答案:

编辑：