Question

我希望在xml中定义的单个onClick函数中存在多个toast。

public void confirm(View v) {
    Name = text1.getText().toString();
    age = text2.getText().toString();
    phonenumber = text3.getText().toString();
    gender="";

    if(r1.isChecked())
        gender="MALE";
    else if(r2.isChecked())
        gender="FEMALE";
    else
        Toast.makeText(getApplicationContext(),"Select Gender",Toast.LENGTH_LONG).show();
    if (Name.length()==0)
        Toast.makeText(getApplicationContext(),"Name Is A Mandatory Field",Toast.LENGTH_LONG).show();
    if(age.length()>3 || age.length()==0)
        Toast.makeText(getApplicationContext(),"Enter Correct Age",Toast.LENGTH_LONG).show();
    if(age.length()>0 && Name.length()>0 && gender.length()>0 && phonenumber.length()>0)
        Toast.makeText(getApplicationContext(), "OTP Sent", Toast.LENGTH_LONG).show();

    }
}

这似乎不起作用。只有性别工作。其他人根本不工作。

Answer 1

这将捕获先出现的错误。我建议按照UI中输入字段的顺序对它们进行排序。

if(!r1.isChecked && !r2.isChecked)
    Toast.makeText(getApplicationContext(),"Select Gender",Toast.LENGTH_LONG).show();
else if (Name.length()==0)
    Toast.makeText(getApplicationContext(),"Name Is A Mandatory Field",Toast.LENGTH_LONG).show();
else if(age.length()>3 || age.length()==0)
    Toast.makeText(getApplicationContext(),"Enter Correct Age",Toast.LENGTH_LONG).show();
else if(age.length()>0 && Name.length()>0 && gender.length()>0 && phonenumber.length()>0)
    Toast.makeText(getApplicationContext(), "OTP Sent", Toast.LENGTH_LONG).show();
else if(r1.isChecked()) 
    gender="MALE";
else if(r2.isChecked())
    gender="FEMALE";

这不是验证用户输入的理想方式。让多个吐司一个接一个地出现并不是一个好主意。在网站中，如果用户错过了多个字段，您可以输入自定义通知，请输入所有字段，或者只是将错过的第一个字段的通知设置好，然后在完成后，将显示下一个丢失的字段通知。 / p>

Answer 2

使用if（Name.trim（）。equals（“”））而不是if（Name.length == 0）

public void confirm(View v) {
    Name = text1.getText().toString();
    age = text2.getText().toString();
    phonenumber = text3.getText().toString();
    gender="";

    if(r1.isChecked())
        gender="MALE";
    else if(r2.isChecked())
        gender="FEMALE";
    else
        Toast.makeText(getApplicationContext(),"Select Gender",Toast.LENGTH_LONG).show();
    **if (Name.trim().equals(""))**
        Toast.makeText(getApplicationContext(),"Name Is A Mandatory Field",Toast.LENGTH_LONG).show();
    **if(age.length()>3 || age.trim().equals(""))**
        Toast.makeText(getApplicationContext(),"Enter Correct Age",Toast.LENGTH_LONG).show();
    if(age.length()>0 && Name.length()>0 && gender.length()>0 && phonenumber.length()>0)
        Toast.makeText(getApplicationContext(), "OTP Sent", Toast.LENGTH_LONG).show();
}

Android多个Toast

2 个答案: