Question

这会产生所需的输出但是我可以看到它不是一个优雅的解决方案（重复三个类似的循环）。这怎么可以浓缩？它可以缩小到多远，使其成为尽可能短/优雅的解决方案？提前致谢

for planet in range(1): #this produces the rows (is this line needed?)


    for column in range(1,6): #this produces the numbers
        print(column, end="***") 
    print()
    for column in range(6,11):
        print(column,end="***")
    print()
    for column in range(11,15):
        print(column,end="***")
    print()

Answer 1

你可以这样做：

for item in range(1,16):
    if item % 5 == 0:
        print(item, "***", sep='')
        continue

    print(item, "***", sep='',end='')

它也会返回相同的结果。

1***2***3***4***5***
6***7***8***9***10***
11***12***13***14***15***

您也可以在函数中替换变量以使其更具可读性，并且如果您需要修改行数和数量。列。

numColumns = 5
numValues = 15

for item in range(1,numValues+1):
    if item % numColumns == 0:  # If it is the last column in the row
        print(item, "***", sep='')  # Print the final column and a newline character (the default end character)
        continue  # Last column in row, skip the rest of the for loop and return to beginning

    print(item, "***", sep='',end='')  # Print the first few columns without a newline end character


# in the print() function:
#  'sep' is the separator between items in the print() function
#  'end' is the special character at the end of the print statement, which is by default the newline '\n'

Python - 更优雅的解决方案？

1 个答案: