在范围内求和

Question

问题是'TypeError：'int'对象不可订阅'，对于我完美的方程序，这里是程序出错的地方：

tested_number = input('What number do you want to test, maximum is 10000? ')    
y = 0   
sum_of_number = sum(int(y) for y in tested_number)#the sum of all the number in the list, highest is 36 due to 10000 limit
digital_root = sum_of_number[0] + sum_of_number[1]
if digital_root == (2, 3, 5, 6, 8, 9):
    print(tested_number, 'is not a perfect square')
    pass
print(tested_number, 'is a perfect square')

Answer 1

当你说：

for y in tested_number

您正在尝试迭代分配给tested_number的整数。你不能这样做。我不确定您打算将哪个变量作为列表，但y或tested_number都不是列表。

Answer 2

当我运行你的程序时，我得到了

$ python3 b.py
What number do you want to test, maximum is 10000? 456
Traceback (most recent call last):
  File "b.py", line 4, in <module>
    digital_root = sum_of_number[0] + sum_of_number[1]
TypeError: 'int' object is not subscriptable

在您的问题中显示完整的回溯非常有用，因为我们都可以确切地看到哪条线路出现故障。看看你的代码

sum_of_number = sum(int(y) for y in tested_number)#the sum of all the number in the list, highest is 36 due to 10000 limit

它非常直接。 sum_of_number是int（这是您期望的数字总和），int无法下标。

Answer 3

在范围内求和

如果您希望将范围总和到测试编号，请尝试以下操作：

tested_number = input('What number do you want to test, maximum is 10000? ')    
sum_of_number = sum(y for y in range(tested_number))
print sum_of_number

What number do you want to test, maximum is 10000? 20
190

在Python程序中键入错误，'int'对象不可订阅'

3 个答案:

在范围内求和