Question

我正在编写一个版本的刽子手作为作业，我已经对这些指示感到困惑。但是，我想将STL列表传递给我创建的类的函数。为了在不同的状态下打印我的刽子手，例如头部，身体，左臂等。我的代码大部分都是：

#include <iostream>
#include <string>
#include <list>
#include "slot.h"

using namespace std;

int main()
{

    string head[4] = {"\t\t  *****", "\t\t  *  *", "\t\t  *  *", 
                      "\t\t  *****"};

    string body[10] = {"\t\t  *****", "\t\t  *   *", "\t\t  *   *", 
                       "\t\t  *****", "\t\t    |", "\t\t    |",
                       "\t\t    |", "\t\t    |", "\t\t    |"};

    string leftarm[10] = {"\t\t  *****", "\t\t  *   *", "\t\t  *   *", 
                          "\t\t  *****", "\t\t\\  |", "\t\t \\ |",
                          "\t\t  \\|", "\t\t    |", "\t\t    |", "\t\t    |"};

    string rightarm[10] = {"\t\t  *****", "\t\t  *   *", "\t\t  *   *", 
                           "\t\t  *****", "\t\t \\  |  /", "\t\t  \\ | /",
                           "\t\t   \\|/", "\t\t    |", "\t\t    |", 
                           "\t\t    |"};

    string leftleg[13] = {"\t\t  *****", "\t\t  *   *", "\t\t  *   *", 
                          "\t\t  *****", "\t\t \\  |  /", "\t\t  \\ | /",
                          "\t\t   \\|/", "\t\t    |", "\t\t    |", 
                          "\t\t    |", "\t\t   /", "\t\t  /", "\t\t /",};

    string rightleg[13] = {"\t\t  *****", "\t\t  *   *", "\t\t  *   *", 
                           "\t\t  *****", "\t\t \\  |  /", "\t\t  \\ | /",
                           "\t\t   \\|/", "\t\t    |", "\t\t    |",
                           "\t\t    |", 
                           "\t\t   / \\",
                           "\t\t  /   \\",
                           "\t\t /     \\",};

    string holdword = "";
    list<string> hanglist;

    for (int j = 0; j < 4; j++) {
        holdword = head[j];
        hanglist.push_back(holdword);
        holdword = "";
    }
    for (int j = 0; j < 10; j++) {
        holdword = body[j];
        hanglist.push_back(holdword);
        holdword = "";
    }
    for (int j = 0; j < 10; j++) {
        holdword = leftarm[j];
        hanglist.push_back(holdword);
        holdword = "";
    }
    for (int j = 0; j < 10; j++) {
        holdword = rightarm[j];
        hanglist.push_back(holdword);
        holdword = "";
    }
    for (int j = 0; j < 13; j++) {
        holdword = leftleg[j];
        hanglist.push_back(holdword);
        holdword = "";
    }
    for (int j = 0; j < 13; j++) {
        holdword = rightleg[j];
        hanglist.push_back(holdword);
        holdword = "";
    }


    DisplayHangman(hanglist);

    Slot temp;
    temp.DisplayHang(hanglist);

    hanglist.clear(); 
    return 0;
}

这是类和头文件：

//********************************************
// This slot.cpp class is designed and created
// to supply the appropriate observer and
// mutator methods.
//********************************************
#include <iostream>
#include <list>
#include <string>
#include "slot.h"

using namespace std;

Slot::Slot()
{
    list<string> holdlist(60);
}

void DisplayHangman(list<string>& hanglist) {

    holdlist = hanglist;

    string hangword = "";

    int lstsize = 0;

    lstsize += hanglist.size();

    for (int i = 0; i < lstsize; i++) {

        string diphang = holdlist.front();
        holdlist.pop_front();
        hangword = diphang;
        cout << hangword << endl;
        hangword = "";
    }
    lstsize = 0; 
    holdlist.clear();

}
Slot::~Slot() {}
#include <iostream>
#include <list>
#include <string>

class Slot
{
public:
    Slot();

    void DisplayHangman(list<string>& hanglist);
    private:
       list<string> holdlist(60);

};
Slot::~Slot()

我很沮丧，我真的打了一张桌子，手骨折了！这是否符合我的想法？

将列表作为参数传递给已从另一个类中抽象出来的函数？

我只是想对它进行单元测试。

Answer 1

DisplayHangman和slot中使用的main()未被声明。
班级Slot没有会员DisplayHang。
Slot:Slot()中有一个无意义的声明和初始化局部变量。

void DisplayHangman(list<string>& hanglist)

slot.cpp

(60)将发出编译错误。
list和string。
Slot::~Slot()不是它应该的位置。

更正后的代码：

main()函数的最后一部分：

    for (int j = 0; j < 13; j++) {
        holdword = rightleg[j];
        hanglist.push_back(holdword);
        holdword = "";
    }

    Slot temp;
    temp.DisplayHangman(hanglist);

    hanglist.clear(); 
    return 0;
}

slot.cpp中的函数定义：

Slot::Slot() : holdlist(60)
{
}

void Slot::DisplayHangman(list<string>& hanglist) {

    // implementation should be same as the original, omitted

}
Slot::~Slot() {}

头文件：

#include <list>
#include <string>

class Slot
{
public:
    Slot();
    ~Slot();

    void DisplayHangman(std::list<std::string>& hanglist);
    private:
       std::list<std::string> holdlist;

};

尝试将STL列表<string>作为参数传递给C ++中的类

1 个答案: