Question

我有一个数据库中的地方表，它包含两行标题和描述

我通过PHP和MYSQL进行搜索

$select_place = $mysqli->query("SELECT * FROM places where title LIKE '%$searchname%' or description LIKE '%$searchname%'");
$num_place = $select_place->num_rows;

while ($rows_place = $select_place->fetch_array(MYSQL_ASSOC)){

$id_place            = $rows_place ['id'];
$title_place         = $rows_place ['title'];
$description_place   = $rows_place ['description'];

echo "<p>{$title_place}</p><br>";

}

它运作良好，但是，例如，如果你搜索单词tower如果以错误的方式写作如twer或towr它不起作用我怎样才能使它更聪明？

Answer 1

一个好的选择是包含MySQL SOUNDEX()函数：

SELECT
    *
FROM
    places
WHERE
    title LIKE '%$searchname%'
    OR description LIKE '%$searchname%'
    OR SOUNDEX(title) = SOUNDEX('$searchname')
    OR SOUNDEX(description) = SOUNDEX('$searchname')

这将匹配您示例中的towr和twer。

更多信息可以在这里找到：

http://dev.mysql.com/doc/refman/5.7/en/string-functions.html#function_soundex

请注意：

目前实施的这项功能旨在与之合作仅限英语的字符串。其他字符串语言可能无法产生可靠的结果。

Answer 2

我找到了非常有用的方法

这里是

$searchname = stringsafe($_GET['search']);
$searchname2 = explode(" ", $searchname);
$query = "SELECT * FROM places WHERE ";

foreach ($searchname2 as $each) {
    $i++;

    if($i == 1){
        $query .= " title LIKE '%$each%'
    OR description LIKE '%$each%'
    OR SOUNDEX(title) = SOUNDEX('$each')
    OR SOUNDEX(description) = SOUNDEX('$each')";
    }else{
        $query .= " OR title LIKE '%$each%'
    OR description LIKE '%$each%'
    OR SOUNDEX(title) = SOUNDEX('$each')
    OR SOUNDEX(description) = SOUNDEX('$each')";
    }
}

$select_place = $mysqli->query("$query limit 20");
$num_place = $select_place->num_rows;

if($num_place == 0){
    echo "<div class='message-no'>No results</div>";
}
else{

while ($rows_place = $select_place->fetch_array(MYSQL_ASSOC)){

$id_place            = $rows_place ['id'];
$title_place         = $rows_place ['title'];
$description_place   = $rows_place ['description'];

echo $title_place."<br>";

}

如何通过php和mysql进行更智能的搜索

2 个答案: